One who voluntarily donates tissues/ organs striped

Makala arrives late to class and misses the first few minutes of the lecture. These are the notes she takes:

lukranit [14]

Answer:

B. Quantum Mechanics

Explanation:

Quantum mechanics is the foundation of all quantum physics including quantum chemistry, quantum field theory, and quantum information science.

4 0

3 years ago

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A car speeds over a hill past point A, as shown in the figure. What is the maximum speed the car can have at point A such that i

Lubov Fominskaja [6]

Answer:

11.8 m/s

Explanation:

At the top of the hill, there are two forces on the car: weight force pulling down (towards the center of the circle), and normal force pushing up (away from the center of the circle).

Sum of forces in the centripetal direction:

∑F = ma

mg − N = m v²/r

At the maximum speed, the normal force is 0.

mg = m v²/r

g = v²/r

v = √(gr)

v = √(9.8 m/s² × 14.2 m)

v = 11.8 m/s

3 0

3 years ago

In graphing enthalpy entropy and state changes which two variables are included ? A. volume and temperature B. amount of heat ad

Blababa [14]

In graphing enthalpy entropy and state changes the two variables that are included are amount of heat added and pressure. The answer is letter D. The rest of the choices do not answer the question above.

7 0

4 years ago

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Using Hooke's law, F spring=k delta x, find the distance a spring with an elastic constant of 4 N/cm will stretch if a 2 newton

pishuonlain [190]

Hello!

Using Hooke's law, F spring=k delta x, find the distance a spring with an elastic constant of 4 N/cm will stretch if a 2 newton force is applied to it.

Data:

Hooke represented mathematically his theory with the equation:

F = K * Δx

On what:

F (elastic force) = 2 N

K (elastic constant) = 4 N/cm

Δx (deformation or elongation of the elastic medium or distance from a spring) = ?

Solving:

$F = K * \Delta{x}$

$2\:N = 4\:N/cm*\Delta{x}$

$4\:N/cm*\Delta{x} = 2\:N$

$\Delta{x} = \dfrac{2\:\diagup\!\!\!\!\!N}{4\:\diagup\!\!\!\!\!N/cm}$

simplify by 2

$\Delta{x} = \dfrac{2}{4}\frac{\div2}{\div2}$

$\boxed{\boxed{\Delta{x} = \dfrac{1}{2}\:cm}}\Longleftarrow(distance)\end{array}}\qquad\checkmark$

Answer:

B.) 1/2 cm

_______________________

I Hope this helps, greetings ... Dexteright02! =)

7 0

3 years ago

The length of a certain wire is kept same while its radius is doubled. what is the change in the resistance of this wire?

kaheart [24]

The resistance of a wire is given by
$R= \frac{\rho L}{A}$
where $\rho$ is the resistivity of the material, L the length of the wire and A its cross-sectional area.

In the problem, $\rho$ and L remain the same, while A changes because the radius changes. The area is given by:
$A=\pi r^2$
This means that if we double the radius (2r), the area becomes
$A_{new}= \pi (2r)^2 = 4 \pi r^2 =4A$
And therefore, the new value of the resistance is
$R_{new} = \frac{\rho L}{4 A}= \frac{1}{4}R$

So, when the radius is doubled, the resistance becomes $\frac{1}{4}$ of its original value.

6 0

4 years ago