Answer:
Distance =
a
2
+b
2
−2abcosθ
=
101
2
+77
2
−2×101×77×cos(25.6
0
)
which gives,
10201+5929−15554×0.8928
=45.85 which is nearly 46 ly.
Explanation:
:)
A-The trip is 6.38 hours long B-The average velocity would be 76.8 km/h
Answer:
10.65 m/s
Explanation:
Given that an Olympic diver is on a diving platform 5.70 m above the water. To start her dive, she runs off of the platform with a speed of 1.27 m/s in the horizontal direction.
Her initial velocity U = 1.27 m/s
The height H = 5.7 m
The final velocity V will be calculated by using the formula;
V^2 = U^2 + 2gH
Substitute U, g and H into the formula
V^2 = 1.27^2 + 2 × 9.8 × 5.7
V^2 = 1.6129 + 111.72
V^2 = 113.33
V = sqrt ( 113.33)
V = 10.65 m/s
Therefore, the diver's speed, in m/s, just before she enters the water is 10.65
Answer:
For outer points of shell
Now for inner point of shell
Explanation:
As we know that out side the shell electric potential is given as
inside the shell the electric potential is given as
now we know the relation between electric potential and electric field as
so we can say for outer points of the shell
Now for inner point again we can use the same