Answer is: pH of hydrazine conjugate acid is 4.088.
Chemical reaction: N₂H₅⁺ + H₂O ⇄ N₂H₄ + H₃O⁺.
[N₂H₅⁺] = 2.0 M.
[N₂H₄] = [H₃O⁺] = x.
Kb(N₂H₄) = 3.0·10⁻⁶.
Kb·Ka = 1.00·10⁻¹⁴.
Ka(N₂H₅⁺) = 1.00·10⁻¹⁴ ÷ 3.0·10⁻⁶.
Ka = 3.33·10⁻⁹.
Ka = [N₂H₄]·[H₃O⁺] / [N₂H₅⁺].
3.33·10⁻⁹ = x² / 2.0 M.
x = [H₃O⁺] = √3.33·10⁻⁹ · 2.0 M.
[H₃O⁺] = 8.1·10⁻⁵ M.
pH = -log[H₃O⁺].
pH = -log(8.1·10⁻⁵ M).
pH = 4.088.
Answer:
Strong acid
Explanation:
An acid is a substance that interacts with water to produce excess hydroxonium ions in an aqueous solution.
Hydroxonium ions are formed as a result of the chemical bonding between the oxygen of water molecules and the protons released by the acid due to its ionisation. This makes aqueous solution of acids conduct electricity.
A strong acid is one that ionizes almost completely. Examples are:
1. Hydrochloric acid
2. Tetraoxosulphate (VI) acid
3. Trioxonitrate (V) acid
4. Hydroiodic acid
5. Hydrobromic acid
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