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Sunny_sXe [5.5K]
3 years ago
5

A weather system moving through the American Midwest produced rain with an average pH of 5.02. By the time the system reached Ne

w England, the rain it produced had an average pH of 4.66. How much more acidic was the rain falling in New England?
Chemistry
1 answer:
bulgar [2K]3 years ago
4 0

Answer:

The rain falling in New England is 2.29 times more acidic than the one in the American Midwest.

Explanation:

The acidity of a solution depends on the concentration of H⁺ ions ([H⁺]). We can calculate this concentration from the pH using the following expression.

pH = -log ([H⁺])

American Midwest

pH = -log ([H⁺])

5.02 = -log ([H⁺])

[H⁺] = antilog (-5.02) = 9.55 × 10⁻⁶ M

New England

pH = -log ([H⁺])

4.66 = -log ([H⁺])

[H⁺] = antilog (-4.66) = 2.19 × 10⁻⁵ M

The ratio of concentrations is:

\frac{2.19 \times 10^{-5} M  }{9.55 \times 10^{-6} M} =2.29

The rain falling in New England is 2.29 times more acidic than the one in the American Midwest.

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Combustion of hydrocarbons such as propane ( C3H8 ) produces carbon dioxide, a "greenhouse gas." Greenhouse gases in the Earth's
Naddika [18.5K]

Answer:

1. C₃H₈(g) + 5O₂ (g)  → 3CO₂ (g) + 4H₂O (g)

2. The volume of CO₂ produced is 238 l.

Explanation:

Hi there!

The chemical equation is the following:

C₃H₈(g) + 5O₂ (g)  → 3CO₂ (g) + 4H₂O (g)

The molar mass of propane is calculated as follows:

mass of 1 mol carbon = 12 g

mass of 1 mol hydrogen = 1 g

mass of 1 mol propane 3 · (12 g) + 8 · (1 g) = 44 g

If we have 150 g of propane, we will have (150 g · 1 mol / 44 g) 3.4 mol propane.

Looking at the chemical equation, notice that 1 mol propane produces 3 mol CO₂. Then 3.4 mol of propane will produce:

(3.4 mol C₃H₈ ·  3 mol CO₂ / mol C₃H₈ ) 10.2 mol CO₂

Using the Ideal Gas Law we can obtain the volume of CO₂ produced:

P · V = n · R · T

Where:

P = pressure.

V = volume

n = number of moles.

R = gas constant (0.082 atm · l / ( K · mol))

T = temperature in kelvin.

V = n · R · T / P

V = 10.2 mol · 0.082 atm · l/ (K mol) · 285 K / 1 atm

Notice that 12 °C = 273  + 12  = 285 K

V = 238 l

The volume of CO₂ produced is 238 l.

Have a nice day!

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H3C-cl
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We assume that Carbon 14/ Carbon 12 ratio was steady for living organisms over time, the problem is actually telling us that
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Take the natural logarithm and In on both sides.
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