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3 years ago

The force that keeps the planets in orbit is________.

Chemistry

1 answer:

erma4kov [3.2K]3 years ago

4 0

Answer:

The force that keeps the planets in orbit is gravity.

You might be interested in

How are a mole and a dozen similar

otez555 [7]

A mole is the same idea as a dozen, but the number involved is a lot bigger than 12. In fact, one mole is equal to 6.02 x 1023 items. This number is also called Avogadro's Number, and is sometimes abbreviated NA. Memorize this conversion factor!

6 0

3 years ago

I am confused, can somebody help me?

Ronch [10]

Answer:

electrons 79

neutrons 188

6 0

3 years ago

Read 2 more answers

BRAINLIEST GIVE AWAY! Please give the correct answer I will reward you with Brainliest!

harkovskaia [24]

Molar mass is the mass of each element multiplied by subscript, then added together.

So, we’ll do

C = 12g x 12 = 144 g
H = 1g x 22 = 22 g
O = 16g x 11 = 176 g

The total of all of these is the molar mass: 342 g in a mol

The amount of mols of each element in each compound is likely equal to its subscripts.

C = 12 mols
H = 22 mols
O = 11 mols

For the atoms, you’ll multiply each one of the above by Avogadro’s number

Avogadro’s Number: 6.02 x 10^23 atoms/mol

7 0

3 years ago

the empirical formula for a compound used as a green paint pigment is C2H3As3Cu2O8. The molar mass of its molecular formula was

melisa1 [442]

Answer:

Molecular formula = C₄H₆As₆Cu₄O₁₆

Explanation:

Given data:

Empirical formula = C₂H₃As₃Cu₂O₈

Molar mass of compound = 1013 g/mol

Molecular formula = ?

Solution:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

Empirical formula mass of C₂H₃As₃Cu₂O₈ is 506.897 g/mol

by putting values.

n = 1013 / 506.897

n = 2

Molecular formula = n (empirical formula)

Molecular formula = 2 (C₂H₃As₃Cu₂O₈)

Molecular formula = C₄H₆As₆Cu₄O₁₆

3 0

3 years ago

Please help, I really don’t understand this!!!

kap26 [50]

Analysing the Question:

We are given the balanced equation:

C₆H₁₂O₆ + 6O₂→ 6CO₂ + 6H₂O

from this equation, we can say that: for every 1 mole of Glucose, we need 6 moles of Oxygen

Moles of Glucose used in the reaction:

Molar mass of Glucose = 180 grams / mol

Given mass of Glucose = 1 gram

Mole of Glucose = Given mass / Molar mass

Moles of Glucose = 1 / 180 moles

Mass of Oxygen required:

We know that for every mole of Glucose, we need 6 moles of Oxygen

So, for 1/180 moles of Glucose, we need 6 / 180 = 1 / 30 moles of Oxygen

Mass of 1 / 30 moles of Oxygen:

Mass = Molar mass * number of moles

Mass of Oxygen = 32 * 1/30

Mass of Oxygen = 32 / 30

Mass of Oxygen = 1.06 grams

5 0

3 years ago