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3 years ago

Cacl2+na3po4 ca3po42 + nacl

Chemistry

1 answer:

Alex787 [66]3 years ago

5 0

<h3>Answer:</h3>

3CaCl₂ + 2Na₃PO₄→ Ca₃(PO₄)₂ + 6NaCl

<h3>Explanation:</h3>

We are given the Equation;

CaCl₂ + Na₃PO₄→ Ca₃(PO₄)₂ + NaCl

Assuming the question requires us to balance the equation;

A balanced chemical equation is one that has equal number of atoms of each element on both sides of the equation.
Balancing chemical equations ensures that they obey the law of conservation of mass in chemical equations.
According to the law of conservation of mass in chemical equation, the mass of the reactants should always be equal to the mass of the products.
Balancing chemical equations involves putting appropriate coefficients on the reactants and products.

In this case;

To balance the equation we are going to put the coefficients 3, 2, 1, and 6.

Therefore; the balanced equation will be;

3CaCl₂ + 2Na₃PO₄→ Ca₃(PO₄)₂ + 6NaCl

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GrogVix [38]

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4 0

3 years ago

Determine the theoretical yield of HCl if 60.0 g of BC13 and 37.5 g of H20 are reacted according to the following balanced react

Pie

Answer : The theoretical yield of HCl is, 56.1735 grams

Explanation : Given,

Mass of $BCl_3$ = 60 g

Mass of $H_2O$ = 37.5 g

Molar mass of $BCl_3$ = 117 g/mole

Molar mass of $H_2O$ = 18 g/mole

Molar mass of $HCl$ = 36.5 g/mole

First we have to calculate the moles of $BCl_3$ and $H_2O$ .

$\text{Moles of }BCl_3=\frac{\text{Mass of }BCl_3}{\text{Molar mass of }BCl_3}=\frac{60g}{117g/mole}=0.513moles$

$\text{Moles of }H_2O=\frac{\text{Mass of }H_2O}{\text{Molar mass of }H_2O}=\frac{37.5g}{18g/mole}=2.083moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$BCl_3(g)+3H_2O(l)\rightarrow H_3BO_3(s)+3HCl(g)$

From the balanced reaction we conclude that

As, 1 mole of $BCl_3$ react with 3 mole of $H_2O$

So, 0.513 moles of $BCl_3$ react with $3\times 0.513=1.539$ moles of $H_2O$

From this we conclude that, $H_2O$ is an excess reagent because the given moles are greater than the required moles and $BCl_3$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $HCl$ .

As, 1 mole of $BCl_3$ react to give 3 moles of $HCl$

So, 0.513 moles of $BCl_3$ react to give $3\times 0.513=1.539$ moles of $HCl$

Now we have to calculate the mass of $HCl$ .

$\text{Mass of }HCl=\text{Moles of }HCl\times \text{Molar mass of }HCl$

$\text{Mass of }HCl=(1.539mole)\times (36.5g/mole)=56.1735g$

Therefore, the theoretical yield of HCl is, 56.1735 grams

7 0

3 years ago

Which element has the LEAST metallic character.

timofeeve [1]

Helium would be the least I think

3 0

3 years ago

Read 3 more answers

Refer to the following compounds.

goblinko [34]

Answer: The answer is D. This has a Carboxylic Acid group, and is acetic acid, or Ethanoic Acid.

ALWAYS LOOK for the Functional Group in question.

A. Would likely not stay in water, or at least not be acidic, for it is butane gas.

B. Is 1-propanol, and alcohols are not acidic as a rule. Certainly not in water.

C. This is an Ether. It will not give up an H+, it it not an acid.

E. This functional group is an amine, which is more “base” like, since the lone pairs of the Nitrogen atom would tend to attract a H+.

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3 years ago

Consider the elements carbon, C and silicon, Si.

Aneli [31]

Answer:

and

Explanation:

All the carbon group atoms, having four valence electrons, form covalent bonds with nonmetal atoms; carbon and silicon cannot lose or gain electrons to form free ions, whereas germanium, tin, and lead do form metallic ions but only with two positive charges

the similarities is that Both carbon and silicon commonly form compounds, easily sharing electrons with other elements. Carbon will make multiple bonds with other carbon molecules by forming single, double and triple covalent bonds. ... Carbon and silicon are often combined, with carbon serving as silicon's backbone.

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2 years ago