Answer:
I am pretty sure it is a watershed
Explanation:
Answer: 252.5 kPa
Explanation:
Given that:
initial volume of gas V1 = 5.00 L
initial pressure of gas P1 = 101 kPa.
new Volume V2 = 2.00 L
new pressure P2 = ?
Since, only pressure and volume are involved, apply the formula for Boyle's law
P1V1 = P2V2
101 kPa x 5.0L = P2 x 2.00L
505 = P2 x 2.00L
P2 = 505/2.00
P2 = 252.5 kPa
Thus, the new pressure of gas inside the piston is 252.5 kPa
Answer:
108.43 grams KNO₃
Explanation:
To solve this problem we use the formula:
Where
- ΔT is the temperature difference (14.5 K)
- Kf is the cryoscopic constant (1.86 K·m⁻¹)
- b is the molality of the solution (moles KNO₃ per kg of water)
- and<em> i</em> is the van't Hoff factor (2 for KNO₃)
We <u>solve for b</u>:
- 14.5 K = 1.86 K·m⁻¹ * b * 2
Using the given volume of water and its density (aprx. 1 g/mL) we <u>calculate the necessary moles of KNO₃</u>:
- 275 mL water ≅ 275 g water
- moles KNO₃ = molality * kg water = 3.90 * 0.275
- moles KNO₃ = 1.0725 moles KNO₃
Finally we <u>convert KNO₃ moles to grams</u>, using its molecular weight:
- 1.0725 moles KNO₃ * 101.103 g/mol = 108.43 grams KNO₃
Answer:
Yes the reaction occur when aqueous solutions happened
