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Semenov [28]
3 years ago
13

How can you test the complete separation of camphor and sand​

Chemistry
2 answers:
Tcecarenko [31]3 years ago
8 0

Answer:

We know that camphor is a sublime substance and sand is not a sublime substance. Thus we can separate camphor from sand by heating the mixture slowly. The vapours of camphor should be then collected and cooled down. We would observe that solid camphor crystals will form.

Explanation:

katrin2010 [14]3 years ago
6 0

Answer: Use own words

What method can be used to separate iron filings and sand?

Iron is magnetic and the other two not, which means a magnet could be used to attract the iron filings out of the mixture, leaving the salt and sand. Salt is water soluble, while sand is not. This means the two can be mixed in water and stirred. The salt will dissolve and the sand will not.

other words

How will you separate Camphor common salt and sand?

Camphor can be separated using sublimation as it is a sublime,common salt and sand mixture can be separated using evaporation and filtration respectively. Principle : Throught sublimation we will get camphor, through decantation sand and then through evaporation salt.

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What do agents such as chemicals, elevated temperatures, ionizing radiation, and viruses have in common?
Leni [432]

Answer:

All of them affect the DNA

Explanation:

Chemicals are compounds that can pass through cell membranes and modificate the DNA, elevated temperatures can denaturalize the cell and therefore damage the DNA, ionizing radiation can pass through cell organelles and reach the nucleus affecting the DNA, and viruses inject its DNA into the genome and modify it.

4 0
3 years ago
Of the following, which is the most concentrated solution?
jeka94
B 1.2g/mL just look at a graph and pin point those answers
8 0
3 years ago
Read 2 more answers
Calculate the acid dissociation constant Ka of a 0.2 M solution of weak acid that is 0.1% ionized is ________.
mars1129 [50]

Answer: acid dissociation constant Ka= 2.00×10^-7

Explanation:

For the reaction

HA + H20. ----> H3O+ A-

Initially: C. 0. 0

After : C-Cx. Cx. Cx

Ka= [H3O+][A-]/[HA]

Ka= Cx × Cx/C-Cx

Ka= C²X²/C(1-x)

Ka= Cx²/1-x

Where x is degree of dissociation = 0.1% = 0.001 and c is the concentration =0.2

Ka= 0.2(0.001²)/(1-0.001)

Ka= 2.00×10^-7

Therefore the dissociation constant is

2.00×10^-7

7 0
3 years ago
Which of the following actions does not require power
Kitty [74]

Answer:

Eating an apple

Explanation:

No electricity

4 0
3 years ago
Calculate the mass of ethyl alcohol required to prepare 540 grams of C4H6, if the reaction follows the scheme:
kkurt [141]

Answer:

Explanation:

2C₂H₅OH    =   C₄H₆  +  2H₂O  +  H₂

2 mole               1 mole

molecular weight of ethyl alcohol

mol weight of C₂H₅OH = 46 gm            

mol weight of C₄H₆  54 gm

540 gm of C₄H₆ = 10 mole

10 mole of C₄H₆ will require 20 mol of ethyl alcohol .

20 mole of ethyl alcohol = 20  x 46

= 920 gm

ethyl alcohol required = 920 gm .

3 0
3 years ago
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