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Answer:
16.4 L
Explanation:
we can use the combined gas law equation that gives the relationship among volume, temperature and pressure conditions of gases.
P1V1/T1 = P2V2/T2
STP conditions are standard temperature and pressure conditions
P1 is standard pressure = 1 atm , T1 is standard temperature = 273 K
and V1 is the volume
P2 is pressure, T2 is temperature and V2 is volume at the second instance
temperature is in kelvin scale,
512 ° + 273 = 785 K
substituting the values in the equation
1 atm x 10.0 L / 273 K = 1.75 atm x V / 785 K
V = 16.4 L
new volume is 16.4 L
<span>The molar volume of a gas at STP, in liters, is 22.4
you then multiply 22.4 by 2 to get the answer to the next question:
</span><span>
You can use the molar volume to convert 2 mol of any gas to 44.8 L
</span>
<span>You can also use the molar volume to convert 11.2 L of any gas to 0.500 mol.
</span>
Avogadro’s law tells you that 1.2 L of O2(g) and 1.2 L of NO2(g<span>) are the same </span><span>numbers of moles of gas.</span>
