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Alenkinab [10]
3 years ago
9

I NEED HELP FAST PLEASE *please answer correctly* Will mark brainliest thank you!!

Chemistry
2 answers:
Dimas [21]3 years ago
8 0

Answer:

i dont know that plzzz help me tooooo

yKpoI14uk [10]3 years ago
5 0

Answer:

Explanation:

Using Charles Law ,

\frac{V1}{T1}=\frac{V2}{T2}

Using this formula we have ,

V1= 200cm^3

T1=40+273.15 = 313.15 K

T2 = 100+273.15 = 373.15 k

V2= ?

Hence using above formula simplify it we will get ,

V2 = 238.3 cm^3

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Which discovery did J. J. Thomson make that improved upon Dalton's atomic theory?
erik [133]

Answer: Atoms contain tiny, negatively charged electrons

Explanation: Thomson's experiments with cathode ray tubes helped him to discover the electron (which Dalton did not know about). Dalton thought that atoms were indivisible particles, and Thomson's discovery of the electron proved the existence of subatomic particles.

3 0
3 years ago
What is the balanced equation for the reaction of aqueous cesium sulfate and aqueous barium perchlorate?
Aleksandr-060686 [28]

Answer:

The balanced chemical reaction is given as:

Cs_2SO_4(aq)+Ba(ClO_4)_2(aq)\rightarrow BaSO_4(s)+2CsClO_4(aq)

Explanation:

When aqueous cesium sulfate and aqueous barium perchlorate are mixed together it gives white precipitate barium sulfate and aqueous solution od cesium perchlorate.

The balanced chemical reaction is given as:

Cs_2SO_4(aq)+Ba(ClO_4)_2(aq)\rightarrow BaSO_4(s)+2CsClO_4(aq)

According to reaction, 1 mole of cesium sulfate reacts with 1 mole of barium perchlorate to give 1 mole of a white precipitate of barium sulfate and 2 moles of cesium perchlorate.

3 0
3 years ago
3 waves are shown with a line through their center. The bottom of the first wave is labeled C. A bracket labeled D connects the
Likurg_2 [28]

Answer:Label the parts of this wave.

A:  

✔ crest

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✔ amplitude

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8 0
3 years ago
Read 2 more answers
A 4.0 L balloon has a pressure of 406 kPa. When the pressure increases to 2,030 kPa, what is the volume? *
elena-14-01-66 [18.8K]

The new volume when pressure increases to 2,030 kPa is 0.8L

BOYLE'S LAW:

The new volume of a gas can be calculated using Boyle's law equation:

P1V1 = P2V2

Where;

  1. P1 = initial pressure (kPa)
  2. P2 = final pressure (kPa)
  3. V1 = initial volume (L)
  4. V2 = final volume (L)

According to this question, a 4.0 L balloon has a pressure of 406 kPa. When the pressure increases to 2,030 kPa, the volume is calculated as:

406 × 4 = 2030 × V2

1624 = 2030V2

V2 = 1624 ÷ 2030

V2 = 0.8L

Therefore, the new volume when pressure increases to 2,030 kPa is 0.8L.

Learn more about Boyle's law calculations at: brainly.com/question/1437490?referrer=searchResults

3 0
3 years ago
Identify the control group the experimental group the independent variable and the dependent variable
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Control group: 50 dogs continuing their normal diet
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