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olganol [36]
3 years ago
10

Why does boiling water in a large pot on a stove have a temperature of 100°C even if it has been boiling for an hour? The temper

ature of a liquid is always the temperature of the gas above it. The temperature of a liquid is always 100°C. The temperature of a substance does not change during a phase change.
Chemistry
2 answers:
lianna [129]3 years ago
7 0

Its because the highest possible temperature of water is 100° C .

tresset_1 [31]3 years ago
3 0

Answer: Option (c) is the correct answer.

Explanation:

Latent heat of vaporization is defined as amount of heat necessary for a unit mass of a liquid to change into vapor state without any change in its temperature.

So, when we boil water in a large pot at 100 degree celsius then its temperature will remain the same unless and until all the bonds between water molecules are broken down.

Temperature of water in this situation will start to change the moment vapors start to form.

Thus, we can conclude that boiling water in a large pot on a stove have a temperature of 100°C even if it has been boiling for an hour because the temperature of a substance does not change during a phase change.

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Which state of matter had the greatest distance the individual particles?
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A chemist titrates 160.0mL of a 0.3403M aniline C6H5NH2 solution with 0.0501M HNO3 solution at 25°C . Calculate the pH at equiva
maxonik [38]

Answer : The pH of the solution is, 5.24

Explanation :

First we have to calculate the volume of HNO_3

Formula used :

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the initial molarity and volume of C_6H_5NH_2.

M_2\text{ and }V_2 are the final molarity and volume of HNO_3.

We are given:

M_1=0.3403M\\V_1=160.0mL\\M_2=0.0501M\\V_2=?

Putting values in above equation, we get:

0.3403M\times 160.0mL=0.0501M\times V_2\\\\V_2=1086.79mL

Now we have to calculate the total volume of solution.

Total volume of solution = Volume of C_6H_5NH_2 +  Volume of HNO_3

Total volume of solution = 160.0 mL + 1086.79 mL

Total volume of solution = 1246.79 mL

Now we have to calculate the Concentration of salt.

\text{Concentration of salt}=\frac{0.3403M}{1246.79mL}\times 160.0mL=0.0437M

Now we have to calculate the pH of the solution.

At equivalence point,

pOH=\frac{1}{2}[pK_w+pK_b+\log C]

pOH=\frac{1}{2}[14+4.87+\log (0.0437)]

pOH=8.76

pH+pOH=14\\\\pH=14-pOH\\\\pH=14-8.76\\\\pH=5.24

Thus, the pH of the solution is, 5.24

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Option C coz it should be ( CNH4)2. Hope i cleared your doubt
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