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olganol [36]
4 years ago
10

Why does boiling water in a large pot on a stove have a temperature of 100°C even if it has been boiling for an hour? The temper

ature of a liquid is always the temperature of the gas above it. The temperature of a liquid is always 100°C. The temperature of a substance does not change during a phase change.
Chemistry
2 answers:
lianna [129]4 years ago
7 0

Its because the highest possible temperature of water is 100° C .

tresset_1 [31]4 years ago
3 0

Answer: Option (c) is the correct answer.

Explanation:

Latent heat of vaporization is defined as amount of heat necessary for a unit mass of a liquid to change into vapor state without any change in its temperature.

So, when we boil water in a large pot at 100 degree celsius then its temperature will remain the same unless and until all the bonds between water molecules are broken down.

Temperature of water in this situation will start to change the moment vapors start to form.

Thus, we can conclude that boiling water in a large pot on a stove have a temperature of 100°C even if it has been boiling for an hour because the temperature of a substance does not change during a phase change.

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14. As the temperature of a gas in a closed container increasses, what is true of the particles in the substance? (2 points)
Ede4ka [16]
The rate of particle movement increases, also increases the pressure in the vessel
4 0
3 years ago
Free brainlist ?!?!?!?!?!?!?!???!?!?!?!?!???!!??!!?!!!?!?!!??
Alchen [17]

Answer:

please?

Explanation:

4 0
3 years ago
Read 2 more answers
Use Q = mcAT
mr Goodwill [35]

Answer:

1).....for the specific heat capacity(c) of water is 4200kg/J°C..

....guven mass(m)=320g(0.32kg)

...change in temperature(ΔT) =35°C

from the formula

Q=mcΔT

Q=0.32Kg x 4200kg/J°C x 35°C

Q=47,040Joules

5 0
3 years ago
Calculate the root mean square (rms) average speed of the atoms in a sample of xenon gas at 0.15 atm and -55c
GrogVix [38]
Answer:
Vrms is 149.7266 m/sec

Explanation:
The root means square velocity of a gas can be calculated as follows:
Vrms = \sqrt{ \frac{3RT}{M}}
where:
R is the ideal gas constant = 8.3145
T is absolute temperature = -55 + 273 = 118 degrees kelvin
M is the molar mass of the gas = 131.293 grams = 0.131293 kg

Substituting with these givens in the above equation, we would find that the Vrms is 149.7266 m/sec

Hope this helps :)
7 0
4 years ago
PLEASE HELP!! GIVING BRAINLIEST
RSB [31]

Answer:

The answer is "0.00172172603".

Explanation:

Given:

Mass (M) = 1.60 \times  10^{-3} \ g\\\\Density (D) = 9.293 \times 10^{-1} \ \frac{g}{cm^3}\\\\Volume (V) =  ?

Formula:

\to \bold{V = \frac{M}{D}}

       = \frac{1.60 \times  10^{-3}}{9.293 \times  10^{-1}} \\\\  = \frac{1.60 \times  10^{1}}{9.293 \times  10^{3}} \\\\ = \frac{1.60 \times  10}{9.293 \times  1000} \\\\ = \frac{1.60 }{9.293 \times  100} \\\\ = \frac{1.60 }{929.3 } \\\\= 0.00172172603

4 0
3 years ago
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