1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
MariettaO [177]
3 years ago
5

Convert 48 000 cg to g

Chemistry
1 answer:
guapka [62]3 years ago
6 0

Answer

The answer is 480g

You might be interested in
At 20 ∘C the vapor pressure of benzene C6H6 is 75 torr and that of toluene C7H8 is 22 torr. Assume that benzene and toluene fo
Olegator [25]

Answer:

a) Xbenzene = 0.283

b) Xtoluene = 0.717

Explanation:

At T = 20°C:

⇒ vapor pressure of benzene (P*b) = 75 torr

⇒ vapor pressure toluene (P*t) = 22 torr

Raoult's law:

  • Pi = Xi.P*i

∴ Pi: partial pressure of i

∴ Xi: mole fraction

∴ P*i: vapor pressure at T

a) solution: benzene (b) + toluene (t)

∴ Psln = 37 torr;   at T=20°C

⇒ Psln = Pb + Pt

∴ Pb = (Xb)*(P*b)

∴ Pt = (Xt)*(P*t)

∴ Xb + Xt = 1

⇒ Psln = 37 torr = (Xb)(75 torr) + (1 - Xb)(22 torr)

⇒ 37 torr - 22 torr = (75 torr)Xb - (22 torr)Xb

⇒ 15 torr = 53 torrXb

⇒ Xb = 15 torr / 53 torr

⇒ Xb = 0.283

b) Xb + Xt = 1

⇒ Xt = 1 - Xb

⇒ Xt = 1 - 0.283

⇒ Xt = 0.717

6 0
4 years ago
1. How many moles of nitrogen monoxide can be made using 5.0 moles of oxygen in the following composition reaction?
Viktor [21]

Answer:

1)  10.0 moles of NO

2) 25 moles of NaCl

3) 1200 moles of CO2

1. How many moles of nitrogen monoxide can be made using 5.0 moles of oxygen in the following composition reaction?

N2 + O2 → 2NO

For 1 mol N2 we need 1 mol O2 to produce 2 moles of NO

For 5.0 moles of N2 we need 5.0 moles of O2 to produce 10.0 moles of NO

2. The neutralization of an acid with a base is a double replacement reaction in which a salt and water are formed. If you start with 25 moles of HCl and neutralize it with  NaOH how many moles of NaCl will be formed?

HCl + NaOH → NaCl + H2O

For 1 mol HCl we need 1 mol NaOH to produce 1 mol of NaCl and 1 mol H2O

For 25 moles of HCl we need 25 moles of NaOH to produce 25 moles of NaCl and 25 moles of H2O

3. A car burns gasoline (octane – C8H18) with oxygen. If you drive to Salt Lake and  burn 150 moles of octane how many moles of carbon dioxide are you producing?

2C8H18 + 25O2 → 16CO2 + 18H2O

For 2 moles of octane we need 25 moles of O2 to produce 16 moles of CO2 and 18 moles of H2O

For 150 moles of octane we need 25*75 = 1875 moles of O2

To produce 16*75 = 1200 moles of CO2 and 18*75= 1350 moles

Explanation:

5 0
3 years ago
Read 2 more answers
I NEED HELP IT GIVES UOU 15 POINTS
Alexxandr [17]

Answer:

I think the answer is: one element and one compound

Explanation:

I'm really sorry if it's wrong.

8 0
3 years ago
What is true about elements in the same periodic
Aleks [24]

Explanation:

Elements that belong to the same period which is seen horizontally in the periodic table have different properties. Elements with similar properties are seen in columns or groups. Elements in the same period have similar principal quantum number and belong to the same principal shell. Hence the answer is that they have different properties that repeat across the next period.

3 0
3 years ago
How to write an informal letter to a friend saying about your science course
Ede4ka [16]
I don’t know what kind of response you want to be written but here are some examples if you are trying to recommend or not recommend your science class to a friend:

Positive View:
Dear (Friend),
My science course is really interesting!
You would not believe the topics we are going to learn this year! We are going to learn about the (topic), (topic), and (topic)! Not only that, did you know that (fun fact)? This science course is probably one of the best classes I ever taken! You should take one of these classes if you are also interested in it.

From your friend, (Name)

Negative View:
Dear (Friend),
My science course is not as interesting and exciting as I thought.. It doesn’t have topics about (topic), (topic), and (topic)... I recommend that you don’t take this course. It really is bad. There is not much to be learned here. But if you really want to join the course, I won’t stop you. After all, that is what you wanted. But I will give good luck to you since you might need it. Don’t say that I didn’t warn you.

From your friend, (Name)

Neutral View:
Dear (Friend),
The science course I’m taking is actually not that bad. It have topics that I don’t really understand but I guess I will just learn it along the school year. If you want to know what kind of topics, the topics they are (topic), (topic), and (topic). They seem hard but if I read from a textbook, I start to understand a bit. Though I wouldn’t recommend it to others, it actually have very interesting knowledge to know about. If you want to join, then join.

From your friend, (Name)
4 0
3 years ago
Other questions:
  • Which of the following best explains why electroplating is a useful process in many industries?
    6·2 answers
  • Is Mg one of the most active elements?
    8·1 answer
  • Diamond and graphitr are made of what
    8·2 answers
  • Which of the following is the best example of a closed system?
    9·2 answers
  • How do Earth's lithosphere,hydrosphere,and atmosphere compare?
    11·2 answers
  • Compare the information provided by a molecules chemical formula to the information provided by its structural formula
    7·1 answer
  • My teacher says protons and electrons are always equal to each other. So does that mean every element has a charge of 0? No, tha
    7·1 answer
  • An electron in a hydrogen atom moves from level 3 to level 1. In a second hydrogen atom, an electron drops from level 2 to level
    5·1 answer
  • Determine el porcentaje masa volumen de una solucion compuesta de 150g de etanol y 20g de agua cuyo volumen total es de 165ml
    6·1 answer
  • 5. A sample of carbon dioxide (CO2) has a mass of 52.0 g.<br> a. How many carbon atoms are present?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!