Answer:
The rate of consumption of is 2.0 mol/L.s
Explanation:
Applying law of mass action to this reaction-
where represents rate of consumption of
,
represents rate of consumption of
,
represents rate of formation of
and
represents rate of formation of
.
Here rate of formation of is 3.0 mol/(L.s)
From the above equation we can write-
Here
So,
Hence,
Answer:
51.2g of CO2
Explanation:
The first step is to balance the reaction equation as shown in the solution attached. Without balancing the reaction equation, one can never obtain the correct answer! Then obtain the masses of octane reacted and carbon dioxide produced from the stoichiometric equation. After that, we now compare it with what is given as shown in the image attached.
