Answer:
A
Explanation:
idk but i do know its right
Particle
wave are the words you're looking for to fill in the blanks
Answer:
14.9802 grams of estrogen must be added to 216.7 grams of benzene.
Explanation:
The relative lowering of vapor pressure of solution containing non volatile solute is equal to mole fraction of solute.
![\frac{p_o-p_s}{p_o}=\frac{n_2}{n_1+n_2}](https://tex.z-dn.net/?f=%5Cfrac%7Bp_o-p_s%7D%7Bp_o%7D%3D%5Cfrac%7Bn_2%7D%7Bn_1%2Bn_2%7D)
Where:
= Vapor pressure of pure solvent
= Vapor pressure of the solution
= Number of moles of solvent
= Number of moles of solute
![p_o = 73.03 mmHg](https://tex.z-dn.net/?f=p_o%20%3D%2073.03%20mmHg)
![p_s= 71.61 mmHg](https://tex.z-dn.net/?f=p_s%3D%2071.61%20mmHg)
![n_1=\frac{216.7 g}{78.12 g/mol}=2.7739 mol](https://tex.z-dn.net/?f=n_1%3D%5Cfrac%7B216.7%20g%7D%7B78.12%20g%2Fmol%7D%3D2.7739%20mol)
![\frac{73.03 mmHg-71.61 mmHg}{73.03 mmHg}=\frac{n_2}{2.7739 mol+n_2}](https://tex.z-dn.net/?f=%5Cfrac%7B73.03%20mmHg-71.61%20mmHg%7D%7B73.03%20mmHg%7D%3D%5Cfrac%7Bn_2%7D%7B2.7739%20mol%2Bn_2%7D)
![n_2=0.05499 mol](https://tex.z-dn.net/?f=n_2%3D0.05499%20mol)
Mass of 0.05499 moles of estrogen :
= 0.05499 mol × 272.4 g/mol = 14.9802 g
14.9802 grams of estrogen must be added to 216.7 grams of benzene.
Answer:
Fire's basic combustion equation is: fuel + oxygen —> carbon dioxide + water, a line many of us had drummed into us by school teachers. However, combustion reactions do not proceed directly from oxygen to carbon dioxide.
Explanation:
Fire's basic combustion equation is: fuel + oxygen —> carbon dioxide + water, a line many of us had drummed into us by school teachers. However, combustion reactions do not proceed directly from oxygen to carbon dioxide.