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umka21 [38]
3 years ago
9

Joan’s initial nickel (II) chloride sample was green and weighed 4.3872 g. After the dehydration reaction and removal of excess

thionyl chloride, the residue was yellow, and had a mass of 2.3921 g.
(a) Was the nickel chloride sample a hydrate? ___________________
(b) If the data indicates a hydrate, calculate x, the number of waters of hydration.
Show your work.
Chemistry
1 answer:
ANEK [815]3 years ago
4 0

Answer:

a) yes, it was an hydrate

b) the number of waters of hydration, x = 6

Explanation:

a) yes it was an hydrate because the mass decreased after the process of dehydration which means removal of water thus some water molecules were present in the sample.

b) NiCl2. xH2O

mass if dehydrated NiCl2 = 2.3921 grams

mass of water in the hydrated sample = mass of hydrated - mass of dehydrated = 4.3872 - 2.3921 = 1.9951 g which represent the mass of water that was present in the hydrated sample.

NiCl2.xH2O

mole of dehydrated NiCl2 = m/Mm = 2.3921/129.5994 = 0.01846 mole

mole of water = m/Mm = 1.9951/18.02 = 0.11072 mole

Divide both by the smallest number of mole (which is for NiCl2) to find the coefficient of each

for NiCl2 = 0.01846/0.01846 = 1

for H2O = 0.11072/0.01846 = 5.9976 = 6

thus the hydrated sample was NiCl2. 6H2O

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7 0
3 years ago
A dunk tank hold 30,533 moles of water? How many grams of water are in the tank?
liubo4ka [24]

The mass of water in the tank, given the data from the question is 549594 g

<h3> Description of mole </h3>

The mole of a substance is related to it's mass and molar mass according to the following equation:

Mole = mass / molar mass

<h3>How to determine the mass of water in the tank</h3>

From the question given above, the following data were obtained:

  • Mole of water = 30533 moles
  • Molar mass of water = 18 g/mol
  • Mass of water = ?

The mass of the water can be obtained as follow:

Mass = mole × molar mass

Mass of water = 30533 × 18

Mass of water = 549594 g

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3 0
1 year ago
An aqueous solution contains 0.23 M potassium hypochlorite.
Arturiano [62]

Answer:

0.22 mol HClO, 0.11mol HBr.

0.25mol NH₄Cl, 0.12 mol HCl

Explanation:

A buffer is defined as a mixture in solution between weak acid and its conjugate base or vice versa.

Potassium hypochlorite (KClO) could be seen as conjugate base of HClO (Weak acid). That means the addition of <em>0.22 mol HClO  </em>will convert the solution in a buffer. HBr reacts with KClO producing HClO, thus, <em>0.11mol HBr</em> will, also, convert the solution in a buffer. 0.23 mol HBr will react completely with KClO and in the solution you will have only HClO, no a buffering system.

Ammonia (NH₃) is a weak base and its conjugate base is NH₄⁺. That means the addition of <em>0.25mol NH₄Cl</em> will convert the solution in a buffer. Also, NH₃ reacts with HCl producing NH₄⁺. Thus, addition of<em> 0.12 mol HCl</em>  will produce NH₄⁺. 0.25mol HCl consume all NH₃.

5 0
3 years ago
I need help with this one guys , anyone can help? <br><br> The answer must be form( pic)
SOVA2 [1]

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