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nikklg [1K]
3 years ago
13

Un grupo de amigos toman un refresco cada uno y deben pagar 9 € por el total de las consumiciones. Como hay dos que solo pueden

poner 1 €, los demás deben aumentar su aportación en 0,25 € cada uno. ¿Cuántos amigos son?
Mathematics
1 answer:
Fed [463]3 years ago
7 0

Answer:

6 friends (4 pay € 1.75 and 2 pay € 1)

Step-by-step explanation:

We have to:

x = friends

y = payment

x * y = 9

y = 9 / x

It follows from the problem:

(x-2) * (y + 0.25) = 9 - 2

(x-2) * (9 / x + 0.25) = 7

x * 9 / x + 0.25 * x - 2 * 9 / x - 2 * 0.25 = 7

9 + 0.25 * x - 18 / x - 0.5 = 7

multiply by 100

100 * 0.25 * x - 100 * 18 / x + 100 * (9 - 0.5 - 7) = 0

25 * x - 1800 / x + 150 = 0

multiply by x

25 * x ^ 2 + 150 * x - 1800 = 0

we factor:

(x - 6) * (x + 12) = 0

x = 6

x = -12

The positive value is taken: x = 6

Each one had to pay = 9/6 = € 1.5

But as two pay € 1, 4 will pay € 0.25 more: 1.5 +0.25 = € 1.75

Thus :

(4 * 1.75) +2 (1) = € 9

Therefore, they are 6 friends (4 pay € 1.75 and 2 pay € 1)

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