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2 years ago

What is the connection between iozination energy, electronegativity, and electron affinity of elements

Chemistry

1 answer:

vivado [14]2 years ago

7 0

Answer:

Explanation:

The three of them increase from left to right across the periods of the periodic table, and at the same time, they decrease from up to down across the groups of the periodic table.

Ionization Energy is defined as the energy required to remove the atom of an electron.

Electron affinity is defined as the change in energy when electron is added to a negative ion.

Electronegativity is the ability of an atom to attract other atoms to itself.

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When molecules have the same number of each element but those atoms are arranged differently they are known as____________.

Karo-lina-s [1.5K]

Answer: Structural Isomers

Explanation:

The compounds having similar molecular formula but different arrangement of atoms or groups in space are called isomers and the phenomenon is called as isomerism.

Isomers are of two types: structural isomers and stereo isomers.

Structural isomers are isomers in which molecules with the same molecular formula have different bonding patterns.

Stereoisomers are isomers in which molecules have the same molecular formula and sequence of bonded atoms but differ in the three-dimensional orientations of their atoms in space.

Thus when molecules have the same number of each element but those atoms are arranged differently they are known as Structural isomers.

5 0

2 years ago

When the following equation is balanced using the smallest possible integers, what is the coefficent of oxygen gas?

elena55 [62]

By balancing a chemical reaction, you must first balance the atom that is in smaller amount in the chemical species that you have in the reaction. In the combustion reaction presented in the question that atom is carbon (C). Therefore, the first thing to do is multiply the CO2 by 7, since those are the carbon atoms that are in the C7H16O. The reaction would be like this,

C7H16O + O2 → 7CO2 + H2O

You can make a table of the amount of atoms of C, H and O that you have in the reagents and products after you put a coefficient 7 in front of the CO2, in the following way,

R P

C 7 7

H 16 2

O 3 15

Then you balance the hydrogens. It is better that you leave the last oxygens since there is an oxygen molecule alone, so when adding a coefficient to balance it, the quantities of the rest of the atoms in the equation would not be altered.

To balance the hydrogens you add an 8 in front of the H2O molecule in the reagents, since there are 16 hydrogens in the molecule C7H16O and

8H x 2H = 16H.

The reaction and the table would be like this,

C7H16O + O2 → 7CO2 + 8H2O

R P

C 7 7

H 16 16

O 3 22

Finally, you balance the atoms of O. To do this, you add a coefficient of 21/2 to the O2 molecule, this is because (21/2) x2 = 21 and 21 O coming from the O2 molecule plus an O coming from the C7H16O molecule gives a total of 22 O, which are equal to the amount of O we have in the products.

C7H16O + (21/2)O2 → 7CO2 + 8H2O

To bring the coefficients of the reactants and the products to whole numbers multiply all the coefficients by 2. Then the reaction is like,

2 C7H16O + 21O2 → 14CO2 + 16H2O

As you can see when the given reaction is balanced using the smallest possible integers, the coefficent of oxygen gas is 21

6 0

3 years ago

Imagine a large compass extending out from center of the earth it set messured 90° One point touches the equator where does the

alexandr402 [8]

The exact opposite end of the earth or 180degrees

6 0

3 years ago

Consider the following reaction, equilibrium concentrations, and equilibrium constant at

REY [17]

Answer:

Equilibrium concentration of $H_{2}O$ is 12.5 M

Explanation:

Given reaction: $C_{2}H_{4}+H_{2}O\rightleftharpoons C_{2}H_{5}OH$

Here, $K_{c}=\frac{[C_{2}H_{5}OH]}{[C_{2}H_{4}][H_{2}O]}$

where $K_{c}$ represents equilibrium constant in terms of concentration and species inside third bracket represent equilibrium concentrations

Here, $[C_{2}H_{4}]=0.015M$ , $[C_{2}H_{5}OH]=1.69M$ and $K_{c}=9.0$

So, $[H_{2}O]=\frac{[C_{2}H_{5}OH]}{[C_{2}H_{4}]\times K_{c}}=\frac{1.69}{0.015\times 9.0}=12.5M$

Hence equilibrium concentration of $H_{2}O$ is 12.5 M

5 0

3 years ago

a chemical company claims that they are able to produce a certain product thermodynamically unfavored process. Explain how this

KonstantinChe [14]

Thermodynamically favored process are those processes that do not require any assistance from outside the system e.g water boils at 25 degrees. Thermodynamically unfavored processes require assistance from outside to induce the required change for example water doesn't freeze at 15 degrees and therefore for that to happen several factors in the system have to be modified to achieve this. Therefore, there is a possibility of companies to produce product by using thermodynamically unfavored process by inducing changes in the system to achieve desired change or modification.

8 0

2 years ago