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Lunna [17]
1 year ago
15

It requires 334 kJ of heat to melt 1 kg of ice. The largest known iceberg had a volume of about 3.1 x 10^13 m³. How much heat wa

s required
to melt the iceberg if 1 m³ of ice has a mass of 917 kg?

Chemistry
1 answer:
Gnesinka [82]1 year ago
5 0

Answer:

3.1×10^13×917= 2842.7×10^13 kg

2842.7×10^13×334=949,461.8×10^13 KJ

Explanation:

First off you convert m³ to kg then convert Kg to Kj

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Photosynthesis is the process by which plants use sunlight, water, and carbon dioxide to create oxygen and energy in the form of sugar.

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How many sig figs are in 0.0003422
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Answer:

4

Explanation:

The zeros before a non zero digit do not count as significant figures so there are 4 sig figs in the number

5 0
3 years ago
If you had a 0.5 M KCl solution, how much solute would you have in moles, and what would the solute be?
Svetradugi [14.3K]

Answer:

37.25 grams/L.

Explanation:

  • Molarity (M) is defined as the no. of moles of solute dissolved per 1.0 L of the solution.

<em>M = (no. of moles of KCl)/(volume of the solution (L))</em>

<em></em>

∵ no. of moles of KCl = (mass of KCl)/(molar mass of KCl)

∴ M = [(mass of KCl)/(molar mass of KCl)]/(volume of the solution (L))

∴ (mass of KCl)/(volume of the solution (L)) = (M)*(molar mass of KCl) = (0.5 M)*(74.5 g/mol) = 37.25 g/L.

<em>So, the grams/L of KCl = 37.25 grams/L.</em>

6 0
3 years ago
The discovery of the electron as a subatomic particle was a result of
swat32

Answer:

4)experiments with cathode ray tubes

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6 0
3 years ago
How many grams of ag can be formed from 5.50 grams of ag2o in the equation: 2ag2o (s) → 4ag (s) o2 (g)?
oee [108]

From the given balanced equation we have find out the amount (in gm) of Ag formed from 5.50 gm of Ag₂O.

2Ag₂O(s) → 4Ag (s) + O₂ (g)

We know, molecular mass of Ag₂O= 231.7 g/mol, and atomic mass of Ag= 107.8 g/mol. Given, mass of Ag₂O=5.50 gm. Number moles of Ag₂O=\frac{5.50}{231.7}= 0.0237 moles.

From the balanced chemical reaction we get 2 (two) moles of Ag₂O produces 4 (four) moles of Ag. So, 0.0237 moles of Ag₂O produces \frac{4X0.0237}{2} moles=0.0474 moles of Ag= 0.0474 X 107.8 g of Ag=5.11g Ag.

Therefore, 5.50 g Ag₂O produces 5.11 g of Ag as per the given balanced chemical reaction.


4 0
3 years ago
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