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2 years ago

How many atoms are in 5.62 moles of Mercury?

Chemistry

1 answer:

Maslowich2 years ago

4 0

Answer:

3.384364 time 10^24 atoms

Explanation:

multiply by avogadro's number

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An unknown liquid has a mass of 30.6 g

Rzqust [24]

Density= 0.585 or 0.59

5 0

3 years ago

50 points!! Brainliest if correct!!

Luda [366]

The answer is C. The answer is C because if u increase the surface area, the more reactants u will get. and if u get more The reactants will move faster. Hoped that Helped!:-)

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2 years ago

A method used by the U.S. Environmental Protection Agency (EPA) for determining the concentration of ozone in air is to pass the

baherus [9]

Answer: 1. $9.08\times 10^{-6}$ moles

2. 90 mg

Explanation:

$O_3(g)+2NaI(aq)+H_2O(l) \rightarrow O_2(g)+I_2(s)+2NaOH(aq)$

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus $4.54 \times 10^{-6}$ moles of ozone is removed by = $\frac{2}{1}\times 4.54 \times 10^{-6}=9.08\times 10^{-6}$ moles of sodium iodide.

Thus $9.08\times 10^{-6}$ moles of sodium iodide are needed to remove $4.54\times 10^{-6}$ moles of $O_3$

2. $\text{Number of moles of ozone}=\frac{0.01331g}{48g/mol}=0.0003moles$

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 0.0003 moles of ozone is removed by = $\frac{2}{1}\times 0.0003=0.0006$ moles of sodium iodide.

Mass of sodium iodide= $moles\times {\text {molar mass}}=0.0006\times 150g/mol=0.09g=90mg$ (1g=1000mg)

Thus 90 mg of sodium iodide are needed to remove 13.31 mg of $O_3$ .

3 0

2 years ago

Balance the equation 2kclo3 3o2 + kcl

sergij07 [2.7K]

Answer is 2KClO3 3O2 + 2KCl

5 0

2 years ago

Why is the piece of coal layered?

marysya [2.9K]

Answer:

Coal is layered because it is a type of sedimentary rock

Explanation:

3 0

2 years ago