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bixtya [17]
3 years ago
8

What is emitted during gamma emission?

Chemistry
1 answer:
Neko [114]3 years ago
6 0

Answer

Light

Explanation:

The gamma emission is an electromagnetic radiation, this kind of radiation come from the light.  

In gamma ray emission, a gamma ray is photon of light. Given that light does not have mass or charge, the symbol we use to identify it is: 00γ. With two zeroes.

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Which has more energy, 500g of ice or 500g of steam
liraira [26]

Answer:

Steam because steam pushes out and ice stays dormant.

Explanation:

5 0
3 years ago
Which geologic features help scientists determine the relative ages of rocks by their positions? Select three options.
stiks02 [169]

Answer:

Option D, Index fossil helps scientists to determine the relative ages of rocks by their positions

Explanation:

Index fossils are arranged in layer in such a way that the lowest layer represent the oldest fossil and the top most layer represents the youngest fossil. Scientist use this concept to determine the relative age of the rocks based on their position beneath the earth’s surface

Hence, option D is correct

7 0
3 years ago
At 850°C, CaCO3 undergoes substantial decomposition to yield CaO and CO2. Assuming that the ΔH o f values of the reactant and pr
Xelga [282]

Answer:

The enthalpy if 68.10 grams of CO2 is produced is  -189.04 kJ

Explanation:

<u>Step 1:</u> Data given

temperature = 850 °C

Mass of 68.10 grams of CO2

ΔH°f (CaO) = -635.6 kJ/mol

ΔH°f (CO2) = -693.5 kJ/mol

ΔH°f (CaCO3) =-1206.9 kJ/mol

<u>Step 2: </u>The balanced equation

CaCO3(s) → CaO(s) + CO2(g)

<u>Step 3:  </u>Calculate ΔH°reaction

ΔH°reaction = ΣΔH°f (products) - ΣΔH°f (reactants)

ΔH°reaction = (ΔH°f (CaO) + ΔH°f (CO2)) -  ΔH°f (CaCO3)

ΔH°reaction = (-635.6 kJ/mol + -693.5 kJ/mol) + 1206.9 kJ/mol

ΔH°reaction = -122.2 kJ /mol

<u>Step 4:</u> Calculate moles of CO2

Moles CO2 = mass CO2 / Molar mass CO2

Moles CO2 = 68.10 grams / 44.01 g/mol

Moles CO2 = 1.547 moles

<u>Step 5:</u> Calculate the enthalpy change for 68.10 grams of CO2

-122.2 kJ/mol * 1.547 moles = -189.04 kJ

The enthalpy if 68.10 grams of CO2 is produced is  -189.04 kJ

7 0
3 years ago
What is the term for the breakdown of glucose in the absence of oxygen?
Tatiana [17]

Answer:

The breakdown of glucose in the absence of oxygen is termed as anaerobic respiration.

Explanation:

Anaerobic respiration or anaerobic oxidation occur in absence of oxygen molecule within the cytoplasm of cell that ultimately leads to the formation of lactate from pyruvate by the catalytic activity of lactate dehydrogenase enzyme.This reaction helps in the regeneration of NAD+.

    During  Anaerobic respiration only 2 molecules of ATP are formed by substrate level phosphorylation .

3 0
3 years ago
To balance a chemical reaction you can list all the atoms on the right and left, then count, and add coefficients until the reac
IrinaVladis [17]

Answer:

I think option 3 is correct

7 0
3 years ago
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