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marin [14]
3 years ago
12

Suppose you failed to mix the borax solution properly. How would this error be reflected in the average titre?

Chemistry
1 answer:
White raven [17]3 years ago
3 0

Answer  and Explanation :

borax is a week base which is used as a primary standard solution to standardize the acid solution there is a very good property of borax that is does not decompose easily as we discussed above that it is a week base does not soluble in water easily, so it is very necessary to proper mixing of borax in water. If there is in proper mixing of borax then it will effect the not standardize the solution and error will be reflected as high alkaline concentration

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Answer:

False, the nucleus is not <em>inside</em> the chromosomes, but the chromosomes are inside the nucleus.

7 0
2 years ago
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Explanation:

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4 0
3 years ago
How many significant figures are in the measurement 81,140 grams
GrogVix [38]
Answer:

5

Explanation:

In order to be able to say how many sig figs are used for the measurement 811.40 g, you need to know that

<span><span>non-zero digits are always significant</span><span>a trailing zero that follows a decimal point and a non-zero digit is always significant</span></span>

In your case, the measurement

<span>811.40</span>

has four non-zero digits and one significant trailing zero.

<span><span><span>8,1,1,4</span>→</span> non-zero digits<span><span>8,1,1,</span>0→</span> significant trailing zero</span>

Therefore, you can say that this measurement has <span>five significant figures</span>

<span>811.40→</span> <span>five significant figures</span>

8 0
3 years ago
Glucose, C 6 H 12 O 6 , is used as an energy source by the human body. The overall reaction in the body is described by the equa
Rufina [12.5K]

Answer : The mass of O_2 required is, 61.82 grams.

Explanation :

First we have to calculate the moles of C_6H_{12}O_6

\text{Moles of }C_6H_{12}O_6=\frac{\text{Given mass }C_6H_{12}O_6}{\text{Molar mass }C_6H_{12}O_6}=\frac{58.0g}{180g/mol}=0.322mol

Now we have to calculate the moles of O_2.

The balanced chemical equation is:

C_6H_{12}O_6(aq)+6O_2(g)\rightarrow 6H_2O(l)+6CO_2(g)

From the balanced reaction we conclude that

As, 1 mole of C_6H_{12}O_6 react with 6 mole of O_2

So, 0.322 moles of C_6H_{12}O_6 react with 0.322\times 6=1.932 moles of O_2

Now we have to calculate the mass of O_2

\text{ Mass of }O_2=\text{ Moles of }O_2\times \text{ Molar mass of }O_2

Molar mass of O_2 = 32 g/mole

\text{ Mass of }O_2=(1.932moles)\times (32g/mole)=61.82g

Therefore, the mass of O_2 required is, 61.82 grams.

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3 years ago
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