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777dan777 [17]
3 years ago
11

1/2x + 1/2x = x + 1 Plzzz help

Mathematics
2 answers:
Naya [18.7K]3 years ago
5 0
There is no solution for this equation.
mart [117]3 years ago
4 0

Answer:

this is the right answer you have.

Step-by-step explanation:

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Ruby and her friends are going into a restaurant. How much would it cost to buy 3
Gnoma [55]

Answer:

Step-by-step explanation:

3x2.25=6.75

4x4=16

16+6.75=22.75

8 0
2 years ago
Does anyone have flvs geometry?​
Anna [14]

Answer:

Step-by-step explanation: I don't

4 0
2 years ago
The standard deviation of the distribution of sample means is​ _______.
luda_lava [24]

Answer:

Standard error

Step-by-step explanation:

The standard deviation of the distribution of sample means is called the standard error of the means.

It is denoted by: \sigma_{\bar X}

The standard error is calculated using the formula: \sigma_{\bar X}=\frac{\sigma}{\sqrt{n} }

where n is the sample size and \sigma is the population standard deviation.

6 0
3 years ago
Do you know how to find rate of change? X&Y intercepts? Zeros?
Rzqust [24]

#Rate of change

Rate of change is slope

If two points be (x1,y-1) and (X2,Y2) then

  • Slope=m=y_2-y_1/x_2-x_1

If a line be ax+by+c=0

  • m=-a/b

#X and y inetercept

If a equation given y=mx+b

  • To find x intercept put y=0
  • To find y inetercept put x=0

#Zeros

To find the zeros spot out the x inetercepts

The x values of the x intercepts are the zeros

3 0
2 years ago
A confidence interval (CI) is desired for the true average stray-load loss u (watts) for a certain type of induction motor when
Genrish500 [490]

Answer:

A) CI = (57.12 , 59.48)

B) CI = (57.71 , 58.89)

C) CI = (57.53 , 59.07)

D) n = 239.63

Step-by-step explanation:

a)

given data:

mean, \bar X = 58.3

standard deviation, σ = 3

sample size, n = 25Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025,

Zc = Z(α/2) = 1.96

ME = Zc * σ \sqrt{n}

ME = 1.96 * 3 \sqrt{25}

ME = 1.18

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 1.96 * 3\sqrt{25} , 58.3 + 1.96 * 3\sqrt{25})

CI = (57.12 , 59.48)

b)

Given data:

mean, \bar X = 58.3

standard deviation, σ = 3

sample size, n = 100

Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025, Zc = Z(α/2) = 1.96

ME = zc * σ \sqrt{n}

ME = 1.96 * 3\sqrt{100}

ME = 0.59

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 1.96 * 3\sqrt{100} , 58.3 + 1.96 * 3\sqrt{100})

CI = (57.71 , 58.89)

c)

sample mean, \bar X = 58.3

sample standard deviation, σ = 3

sample size, n = 100

Given CI level is 99%, hence α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005, Zc = Z(α/2) = 2.58

ME = Zc * σ \sqrt{n}

ME = 2.58 * 3\sqrt{100}

ME = 0.77

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 2.58 * 3\sqrt{100} , 58.3 + 2.58 * 3/\sqrt{100}

CI = (57.53 , 59.07)

D)

Given data:

Significance Level, α = 0.01,

Margin or Error, E = 0.5,

σ = 3

The critical value for α = 0.01 is 2.58.

for calculating population mean we used

n \geq (zc *σ/E)^2

n = (2.58 * 3/0.5)^2

n = 239.63

7 0
3 years ago
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