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mojhsa [17]
3 years ago
15

What is the pH of a solution with [H3O+]= (8.70x10^-5). Enter your answer in scientific notation and with three significant figu

res.
Chemistry
1 answer:
nikklg [1K]3 years ago
6 0

Hey there!:

We know that :

pH = - log [ H₃O⁺ ]

pH = - log [ 8.70 x 10⁻⁵ ]

pH = 4.06

Therefore pH is 4.06

I hope this will help !

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Chemistry Question! 20 Points!
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I guess it's a, because nuclear decay is likely to occur when either the mass or atomic number is greater than 83.

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Calculate the ph of a 0.021 m nacn solution. [ka(hcn) = 4.9  10–10]
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<span>Answer is: pH of solution of sodium cyanide is 11.3.
Chemical reaction 1: NaCN(aq) → CN</span>⁻(aq) + Na⁺<span>(aq).
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c(NaCN) = c(CN</span>⁻<span>) = 0.021 M.
Ka(HCN) =  4.9·10</span>⁻¹⁰<span>.
Kb(CN</span>⁻) = 10⁻¹⁴ ÷ 4.9·10⁻¹⁰ = 2.04·10⁻⁵<span>.
Kb = [HCN] · [OH</span>⁻] / [CN⁻<span>].
[HCN] · [OH</span>⁻<span>] = x.
[CN</span>⁻<span>] = 0.021 M - x..
2.04·10</span>⁻⁵<span> = x² / (0.021 M - x).
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Which gas below has the largest number of moles at STP?
ArbitrLikvidat [17]

Answer:

a.) 22.4 L Ne.

Explanation:

It is known that every 1.0 mol of any gas occupies 22.4 L.

For the options:

  • 22.4 L Ne:

<em>It represents </em><em>1.0 mol of Ne.</em>

<em />

  • 20 L Ar:

using cross multiplication:

1.0 mol occupies → 22.4 L.

??? mol occupies → 20 L.

The no. of moles of (20 L) Ar = (1.0 mol)(20 L)/(22.4 L) = 0.8929 mol.

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using cross multiplication:

1.0 mol occupies → 22.4 L.

??? mol occupies → 2.24 L.

<em>The no. of moles of (2.24 L) Xe </em>= (1.0 mol)(2.24 L)/(22.4 L) = <em>0.1 mol.</em>

  • So, the gas that has the largest number of moles at STP is: a.) 22.4 L Ne.

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