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Vera_Pavlovna [14]
2 years ago
12

  What is the name of this hydrocarbon?

Chemistry
2 answers:
UkoKoshka [18]2 years ago
8 0
Hydrocarbon tells you that it is a <span>six carbon compound containing a triple bond.</span>
lana66690 [7]2 years ago
3 0

Answer : The name of the given hydrocarbon is, 3,3-dimethylhexane

Explanation :

The basic rules for naming of organic compounds are :

  • First select the longest possible carbon chain.
  • The longest possible carbon chain should include the carbons of double or triple bonds.
  • The naming of alkane is done by adding the suffix -ane, alkene by adding the suffix -ene, alkyne by adding the suffix -yne and carboxylic acid by adding the suffix -oic acid.
  • The numbering is done in such a way that first carbon of double or triple bond gets the lowest number.
  • The carbon atoms of the double or triple bond get the preference over the other substituents present in the parent chain.
  • If two or more similar alkyl groups are present in a compound, the words di-, tri-, tetra- and so on are used to specify the number of times of the alkyl groups in the chain.

From the given structure we conclude that, the longest carbon contains 4 carbons and two methyl group are present at 3rd position.

So, the name of the given hydrocarbon is, 3,3-dimethylhexane

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The standard cell potential Ec for the reduction of silver ions with elemental copper is 0.46V at 25 degrees celsius. calculate
Cloud [144]

Answer : The \Delta G for this reaction is, -88780 J/mole.

Solution :

The balanced cell reaction will be,  

Cu(s)+2Ag^+(aq)\rightarrow Cu^{2+}(aq)+2Ag(s)

Here, magnesium (Cu) undergoes oxidation by loss of electrons, thus act as anode. silver (Ag) undergoes reduction by gain of electrons and thus act as cathode.

The half oxidation-reduction reaction will be :

Oxidation : Cu\rightarrow Cu^{2+}+2e^-

Reduction : 2Ag^++2e^-\rightarrow 2Ag

Now we have to calculate the Gibbs free energy.

Formula used :

\Delta G^o=-nFE^o

where,

\Delta G^o = Gibbs free energy = ?

n = number of electrons to balance the reaction = 2

F = Faraday constant = 96500 C/mole

E^o = standard e.m.f of cell = 0.46 V

Now put all the given values in this formula, we get the Gibbs free energy.

\Delta G^o=-(2\times 96500\times 0.46)=-88780J/mole

Therefore, the \Delta G for this reaction is, -88780 J/mole.

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