Honey is a - Mixture
Ink is - Mixture
And Gold Dust is a - Compound
Answer: 12 Protons, 12 electrons and 16 neutrons. The number of protons and electrons always stays the same, but the neutrons is the mass-protons. In this case, 28-12=16 neutrons.
Answer: the second one multiplication
Explanation:
The grams of solid copper oxide must be used to prepare a solution of 0.125m concentration is 5.26 g.
According to the definition of molar concentration of a substance dissolved in a solution is defined as the ratio of the number of moles to the volume of the solution.
C = n/V
The number of moles is equal to the given mass divided by the molar mass.
n = m/Mm = n ×m
Given,
The volume of the solution of copper oxide = 0.53
Molar mass of copper oxide = 79.5
Concentration of copper oxide = 0.125
CuO = cVM
= 0.125 × 0.53 × 79.5
= 5.26g
Thus, we concluded that the grams of solid copper oxide must be used to prepare a solution of 0.125m concentration is 5.26 g.
DISCLAIMER: The above question is wrong. The correct question is
Question: In lab you have to prepare 530. 00 ml solution of 0. 125 m copper (ii) oxide. How many grams of solid copper oxide must be used to prepare a solution of this concentration?
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With that informatio you can:
1) Write the chemical equation
2) Balance the chemical equation
3) State the molar ratios
4) Predict if precipitation occurs.
I will do all four, for you:
1) Chemical equation:
mercury(I) nitrate potassium bromide mercury(I) bromide potassium nitrate
<span>Hg2(NO3)2 + KBr → Hg2Br2 + KNO<span>3
2) Balanced chemical equation
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<span>Hg2(NO3)2 + 2KBr → Hg2Br2 + 2KNO<span>3
3) Molar ratios or proportions:
1 mol </span></span><span>Hg2(NO3)2 : 2 mol KBr : 1 mol Hg2Br2 : 2 mol KNO<span>3
4) Prediction of precipitation.
You can use the solubility rules or a table of solubilities. I found in a table of solutiblities that mercury(I) bromide is insoluble and potassium bromide is soluble, Then you can predict that the precipitation of mercury(I) bromide will occur.
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