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kondor19780726 [428]
3 years ago
11

Using the measurements in the table, determine which unidentified metal has the lowest density

Chemistry
2 answers:
Oliga [24]3 years ago
3 0
C is the correct answer because density is mass per unit volume and when you divide it we that volume is greater than mass so density is less density density is directly proportional to Mass Density is inversely proportional to volume
xxTIMURxx [149]3 years ago
3 0

Answer:

\boxed{\text{Metal c}} }

Explanation:

\text{Density} = \dfrac{\text{mass}}{\text{volume}}\\\\\textbf{a. }\text{Density} = \dfrac{\text{122 g}}{\text{12.5 cm}^{3}} = \text{9.96 g/cm}}^{3}\\\\\textbf{b. }\text{Density} = \dfrac{\text{132 g}}{\text{14.2 cm}^{3}}= \text{9.30 g/cm}}^{3}\\\\\textbf{c. }\text{Density} = \dfrac{\text{126 g}}{\text{18.1 cm}^{3}}= \text{6.96 g/cm}}^{3}\\\\\textbf{d. }\text{Density} = \dfrac{\text{126 g}}{\text{12.7 cm}^{3}}= \text{9.92 g/cm}^{3}\\\\\boxed{\textbf{Metal c}}\text{ has the lowest density}

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3 0
3 years ago
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What is the pH of an acid with a [H+] of 1.0 x 10&amp;-4 M?<br><br> 1. 4<br> 2. 10<br> 3. 1<br> 4. 7
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PH scale is from 1 to 14 and indicates how acidic or basic a solution is. To find pH or pOH we need to know the H⁺ ion concentration or OH⁻ concentration.
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8 0
2 years ago
Consider the reaction given below.
Drupady [299]

Answer:

  • <u>K =  0.167 s⁻¹</u>

Explanation:

<u>1) Rate law, at a given temperature:</u>

  • Since all the data are obtained at the same temperature, the equilibrium constant is the same.

  • Since only reactants A and B participate in the reaction, you assume that the form of the rate law is:

        r = K [A]ᵃ [B]ᵇ

<u>2) Use the data from the table</u>

  • Since the first and second set of data have the same concentration of the reactant A, you can use them to find the exponent b:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₂ = (1.50)ᵃ (2.50)ᵇ = 2.50 × 10⁻¹ M/s

         Divide r₂ by r₁:     [ 2.50 / 1.50] ᵇ = 1 ⇒ b = 0

  • Use the first and second set of data to find the exponent a:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₃ = (3.00)ᵃ (1.50)ᵇ = 5.00 × 10⁻¹ M/s

        Divide r₃ by r₂: [3.00 / 1.50]ᵃ = [5.00 / 2.50]

                                  2ᵃ = 2 ⇒ a = 1

         

<u>3) Write the rate law</u>

  • r = K [A]¹ [B]⁰ = K[A]

This means, that the rate is independent of reactant B and is of first order respect reactant A.

<u>4) Use any set of data to find K</u>

With the first set of data

  • r = K (1.50 M) = 2.50 × 10⁻¹ M/s ⇒ K = 0.250 M/s / 1.50 M = 0.167 s⁻¹

Result: the rate constant is K =  0.167 s⁻¹

6 0
3 years ago
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