Answer:
K = [H2] [CO] / [HCHO]
Explanation:
HCHO(g) ⇌ H2(g) + CO(g)
We can obtain the expression for the equilibrium constant for the above equation as follow:
Equilibrium constant, K for a given reaction is the ratio of the concentration of the product raised to their coefficient to the concentration of the reactant raised to their coefficient.
Thus, the equilibrium constant, K for the above equation can be written as follow:
K = [H2] [CO] / [HCHO]
To calculate moles from grams using chemical formulas ... However, one mole of magnesium weighs 24.31 g. ... 0.873 g x 95.21 g = 9.17 x 10-3 mol MgCl2.
If the humidity of the room is low, the water that contacts the air directly could evaporate and takes some energy from the bulk thus decreasing its temperature steadily. This allows the water to have a lower temperature.
For this problem, let's use the approach of dimensional analysis. This technique is done by cancelling out like units that appear both on the numerator and the denominator side. As a result, this technique will let you know that your final answer conforms to what parameter is asked. In this case, the final answer should be in mL. The solution is as follows:
14.5 mg * 1 mL/25 mg = 0.58 mL
Answer:
a) The volume increases
b) The volume decreases
c) The volume does not change
Explanation:
<em>A gas at a pressure of 2.0 atm is in a closed container. Indicate the changes (if any) in its volume when the pressure undergoes the following changes at constant temperature and constant amount of gas.</em>
<em />
When there is a change in the pressure (P) at constant temperature (T) and amount of gas (n), we can find the change in the volume (V) using Boyle's law.
P₁.V₁ = P₂.V₂
where,
1 refer to the initial state
2 refer to the final state
<em>a) The pressure drops to 0.40 atm.</em>
P₁.V₁ = P₂.V₂
(2.0 atm) . V₁ = (0.40 atm) . V₂
V₂ = 5 . V₁
The volume increases.
<em>b) The pressure increases to 6.0 atm.</em>
P₁.V₁ = P₂.V₂
(2.0 atm) . V₁ = (6.0 atm) . V₂
V₂ = 0.33 . V₁
The volume decreases.
<em>c) The pressure remains at 2.0 atm.</em>
P₁.V₁ = P₂.V₂
(2.0 atm) . V₁ = (2.0 atm) . V₂
V₂ = V₁
The volume does not change.
