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madam [21]
3 years ago
12

A billiard ball moves with 3 kg⋅m/s of momentum and strikes three other billiard balls. What is the total momentum of the balls

after the collision?
(1 point)
more than 3 kg⋅m/s
3 kg⋅m/s
It depends on the mass of each ball.
less than 3 kg⋅m/s
Physics
1 answer:
maxonik [38]3 years ago
3 0

A billiard ball moves with 3 kg⋅m/s of momentum and strikes three other billiard balls that have been just sitting there at rest and not moving.

The total momentum of all four balls after the collision is <em>3 kg⋅m/s</em>, because momentum is not created or destroyed.  The total amount of it after an event is the same as the total amount of it before the event.

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Answer:

   x = 9.32 cm

Explanation:

For this exercise we have an applied torque and the bar is in equilibrium, which is why we use the endowment equilibrium equation

Suppose the counterclockwise turn is positive, let's set our reference frame at the left end of the bar

          - W l / 2 - W_{child} x + N₂ l = 0

             x = \frac{-W l/2 + n_2 l}{W_{child}}             1)

now let's use the expression for translational equilibrium

         N₁ - W - W_(child) + N₂ = 0

indicate that N₂ = 4 N₁

we substitute

           N₁ - W - W_child + 4 N₁ = 0

           5 N₁ -W - W_{child} = 0

           N₁ = ( W + W_{child}) / 5

         

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Particle-X has a speed of 0.720 c and a momentum of 4.350x1019 kgm/s. What is the mass of the particle? 2.0206 10-27 kg Hints: T
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Explanation:

Given that,

Speed of particle = 0.720 c

Momentum = 4.350\times10^{-19}\ kgm/s[/tex]

(I). We need to calculate the mass of the particle

Using formula of momentum

P=mv

m =\dfrac{P}{v}

m=\dfrac{4.350\times10^{-19}}{ 0.720\times3\times10^{8}}

m=2.013\times10^{-27}\ Kg

We need to calculate the rest mass of particle

Using formula of rest mass

m=\dfrac{m_{0}}{\sqrt{1-(\dfrac{v}{c})^2}}

Where, m_{0} = rest mass

Put the value into the formula

m_{0}=2.013\times10^{-27}\times\sqrt{1-(\dfrac{0.720 c}{c})^2}

m_{0}=2.013\times10^{-27}\times\sqrt{1-(0.720)^2}

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(b). We need to calculate the rest energy of the particle

Using formula of energy

E_{0}=m_{0}c^2

Put the value into the formula

E_{0}=1.4\times10^{-27}\times(3\times10^{8})^2

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Using formula of kinetic energy

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K.E=(2.013\times10^{-27}-1.4\times10^{-27})\times3\times10^{8}

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Using formula of energy

E=mc^2

Put the value into the formula

E=2.013\times10^{-27}\times(3\times10^{8})^2

E=1.812\times10^{-10}\ J

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