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nignag [31]
3 years ago
6

Which of the following is true about all electromagnetic waves in a vacuum

Physics
2 answers:
Yakvenalex [24]3 years ago
6 0

They all travel at the same speed!

Helen [10]3 years ago
4 0
Electro waves in a vacuum air is deals with this and electricity when the air and the electricity it  makes electro magnets.
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Um carrinho de mão, que se movimenta sobre uma ponte, como mostra a figura, onde o corpo se desloca do ponto A, considerada posi
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if you spoke english i could more than likely answer this for you thanks!

Explanation:

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How might the velocity (speed) of wind or water affect the deposition of sediments?
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Well depending on the speed of both of those things is were the rock will be placed and it also determines how fast can an environment change
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3 years ago
A thermometer calibrated in the Celsius scale and a thermometer calibrated in the Fahrenheit scale are used to measure the same
Dominik [7]

Answer:

d) may be any of these , depending on the temperature

Explanation:

Let at temperature t , reading of both Celsius and Fahrenheit scale be same

using the formula of conversion

(F - 32) / 9 = C / 5

(t - 32) / 9 = t / 5

5t - 160 = 9t

t = - 40° Celsius .

For temperature above it , reading of  Fahrenheit scale will be more . For temperature below it Fahrenheit scale will show lesser reading than  Celsius

reading .

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3 years ago
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Is poop a biotic or abitotic factor? And what about nest?
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2 years ago
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A car covers 72 kilometers in the first hour of its journey. In the next hour, it covers 90 kilometers. What is the amount of wo
Nina [5.8K]

The work done is 2.8125 \times 10^{5} \mathrm{J}

Work Done = Change in Kinetic Energy (ΔKE)

<u>Explanation</u>

In first 1 hour it travels 72 km

So, Velocity = \frac{\text { distance }}{\text { time }}=\frac{72}{1} k m / h=72 \mathrm{km} / \mathrm{h}=\frac{72000}{3600} \mathrm{m} / \mathrm{s}=20 \mathrm{m} / \mathrm{s}

or, Initial Velocity (u) = 20 m/s

Similarly for the next hour it covers 90 km

So, Velocity = \frac{\text { distance }}{\text { time }}=\frac{90}{1} k m / h=90 \mathrm{km} / \mathrm{h}=\frac{90000}{3600} \mathrm{m} / \mathrm{s}=25 \mathrm{m} / \mathrm{s}

or, Final Velocity (v) = 20 m/s

Work done = Change in Kinetic Energy (ΔKE)

Work done = ΔKE = \frac{1}{2} m v^{2}-\frac{1}{2} m u^{2}

ΔKE = \frac{1}{2} m\left(v^{2}-u^{2}\right)=\frac{1}{2} \times\left(2.5 \times 10^{3}\right) \times\left(25^{2}-20^{2}\right)

= \frac{2500 \times(625-400)}{2}=\frac{2500 \times 225}{2}=\frac{562500}{2}= 281250 joule  

= 2.8125 \times 10^{5} \mathrm{J}

4 0
2 years ago
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