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Ivahew [28]
4 years ago
14

Which statement about a pair of units is true?

Physics
1 answer:
grandymaker [24]4 years ago
3 0

Answer:

option A is correct as 1 yard consist of 0.9144 meter which is less than one meter

Explanation:

from the above given statement option 1 is true

1 yard is equal to 0.9144 meter

while

1 mile is equal to 1.60934 km

1 foot is equal to 30.48 centimeter

1 inch is equal to 2.54 centimeter

therefore all these units [left one] are larger than their respective conversion [ right one unit]

therefore option A is correct as 1 yard consist of 0.9144 meter which is less than one meter

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Monica [59]

Answer:

I can't see the attachment it's too blury I can see bout two words and thats it

Explanation:

Think i got an eye infection or bad eye sight

3 0
3 years ago
The center of gravity of a loaded truck depends on how the truck is packed. If it is 4.0 m high and 2.4 m wide, and its CG is 2.
Vitek1552 [10]

The slope of the road can be given as the ratio of the change in vertical

distance per unit change in horizontal distance.

  • The maximum steepness of the slope where the truck can be parked without tipping over is approximately <u>54.55 %</u>.

Reasons:

Width of the truck = 2.4 meters

Height of the truck = 4.0 meters

Height of the center of gravity = 2.2 meters

Required:

The allowable steepness of the slope the truck can be parked without tipping over.

Solution:

Let, <em>C</em> represent the Center of Gravity, CG

At the tipping point, the angle of elevation of the slope = θ

Where;

tan\left(\theta \right) = \dfrac{\overline{AM}}{\overline{CM}}

The steepness of the slope is therefore;

\mathrm{The \ steepness \  of  \ the  \ slope}= \dfrac{\overline{AM}}{\overline{CM}} \times 100

Where;

\overline{AM} = Half the width of the truck = \dfrac{2.4 \, m}{2} = 1.2 m

\overline{CM} = The elevation of the center of gravity above the ground = 2.2 m

\mathrm{The \ steepness \  of  \ the  \ slope}= \dfrac{1.2}{2.2} \times 100 \approx 54.55\%

tan\left(\theta \right) = \mathbf{\dfrac{2.2}{1.2}} = \dfrac{11}{6}

Elevation \ of \ the \ road \ \theta = arctan\left( \dfrac{6}{11} \right)  \approx 28.6 ^{\circ}

The maximum steepness of the slope where the truck can be parked is <u>54.55 %</u>.

Learn more here:

brainly.com/question/20793607

3 0
3 years ago
A photon of light has a wavelength of about 600 nm (1nm = 1 x 10-9 m). What is the energy of this photon of light? Show all calc
bezimeni [28]
Wavelength = 600 nm = 600 × 10^(-9)
speed of light = c = 3 × 10^8
planck constant = h = 6.63 × 10^(-34)

energy of photon = hc/wavelength
 = 6.63 × 10^(-34) × 3 × 10^8/600 × 10^(-9)
 = 1.9 × 10^(-25)/6 × 10^(-7)
 = 0.31 × 10^(-16)
 = 3.1 × 10^(-17)
6 0
3 years ago
A shaving or makeup mirror is designed to magnify your face by a factor of 1.40 when your face is placed 20.0cm in front of it
Dennis_Churaev [7]

Answer:

(a) convex mirror

(b) virtual and magnified

(c) 23.3 cm

Explanation:

The having mirror is convex mirror.

distance of object, u = - 20 cm

magnification, m = 1.4

(a) As the image is magnified and virtual , so the mirror is convex in nature.

(b) The image is virtual and magnified.

(c) Let the distance of image is v.

Use the formula of magnification.

m =-\frac{v}{u}\\1.4=-\frac{v}{-20}\\v =28 cm

Use the mirror equation, let the focal length is f.

\frac{1}{f}=\frac{1}{v}+\frac{1}{u}\\\frac{1}{f}=\frac{1}{28}+\frac{1}{20}\\\frac{1}{f}=\frac{28+20}{560}\\f=11.67cm

Radius of curvature, R = 2 f = 2 x 11.67 = 23.3 cm

5 0
3 years ago
A 20 kg girl runs up the staircase to a floor 4 m higher in 5 seconds. Whats her power output?​
Zina [86]

Answer:

Explanation:

P = mgh/t = 20(9.8)(4) / 5 = 156.8 W(atts)

6 0
2 years ago
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