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Tresset [83]
3 years ago
15

A particle moves in the xy plane with constant acceleration. At time zero, the particle is at x = 6 m, y = 8.5 m, and has veloci

ty ~vo = (9 m/s) ˆı + (−2.5 m/s) ˆ . The acceleration is given by ~a = (4.5 m/s 2 ) ˆı + (3 m/s 2 ) ˆ . What is the x component of velocity after 3.5 s? Answer in units of m/s.
Physics
1 answer:
andreev551 [17]3 years ago
8 0

Answer:

24.75 m/s

Explanation:

Since it's only asking for the component we can use v_final=v_initial+at which then gives v_final=9+3.5*4.5=24.75 m/s

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A car goes around a curve of radius r at a constant speed v. Then it goes around a curve ofradius 2r at speed 2v. What is the ce
Rainbow [258]

The centripetal force on the car as it goes around the second curve is twice that compared to the first.

What is Centripetal force?

It is the force that is necessary to keep an object moving in a curved path and that is directed inward toward the center of rotation.

The formula of Centripetal force is:

F(c) = (m* v^2) / r

Here,

At the first curve,

The curve of radius = r

The constant speed = v

At the second curve,

The car speed (v')= 2 v

The radius of the curve (r')=2 r

According to the formula of centripetal Force:

As the car goes around the second curve,

F'(c) = m*v'^2 / r'

F'(c) = m* (2*v)^2 / 2r

F'(c) = 2* F

Thus,

The centripetal force on the car as it goes around the second curve is twice that compared to the first.

Learn more about centripetal force here:

<u>brainly.com/question/14317060</u>

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8 0
1 year ago
Can you help me??? This is too hard.
evablogger [386]

Answer:

Vacuum. A sound vacuum was created, i believe.

4 0
3 years ago
C. A helium atom has a diameter of approximately 9.8 • 10-11 meters. What is the diameter of a helium atom in nanometers? Given
Studentka2010 [4]

1\ nm = 10^{-9} m\\\\1\ m =\frac{1\ nm}{10^{-9}}

Since the diameter of helium atom is approximately 9.8\times 10^{-11}\ m, therefore the diameter of helium atom in nano meter,

9.8\times 10^{-11}\ m=9.8\times 10^{-11} \times\frac{1\ nm}{10^{-9}}=0.098\ nm

4 0
3 years ago
When landing after a spectacular somersault, a 35.0 kg gymnast decelerates by pushing straight down on the mat. calculate the fo
Sliva [168]

The deceleration experienced by the gymnast is the 9 times of the acceleration due to gravity.

Now from Newton`s  first law, the net force on gymnast,

F_{net} =F-W=ma

Here, W is the weight of the gymnast and a is the acceleration experienced by the gymnast (9\times g acceleration due to gravity)  

Therefore,

F= ma+W OR F=ma+mg=m(g+a)

Given m = 30 kg anda=9\times g=9\times 9.8 m/s^{2} =88.2 m/s^{2}

Substituting these values in above formula and calculate the force exerted by the gymnast,  

F=(40 kg) (88.2 m/s^{2} +9.8 m/s^{2} )

F=3.537\times10^{3}N

6 0
3 years ago
There is a reflection at the boundary between two materials if there is a change of __________ at the boundary.
melisa1 [442]
<span>The speed of the light in the materials. Hope this helps!!</span>
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3 years ago
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