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Alika [10]
3 years ago
11

On a cold day (0C) you observe a person far away from you hit a piece of metal with a hammer. Then 0.75 seconds later you hear

the sound of the hammer hitting the metal. How far are you from the other person?
Physics
1 answer:
bearhunter [10]3 years ago
3 0

Answer:

248.48 meters

Explanation:

When there is low temperature than the normal room temperature, the speed of sound in air decreases because at lower temperatures the movement of air molecules through which the sound travels gets decreases.

Speed of sound at 0⁰ is found to be approximately 331.3 m/s.

The question says that sound was heard by the observer 0.75 seconds later after hammer hit the metal.

As we know, Distance traveled = Speed × Time taken

So, distance traveled by sound in 0.75 seconds = 331.3 × 0.75 = 248.48 m

So, the observer was standing 248.48 meters away from the other person hitting the hammer.

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What kind of thermal transfer 1.conduction 2.convective 3.radiation from the sun?
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Answer:
Radiation

Explanation:
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On the other hand:
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8 0
3 years ago
(a) Calculate the magnitude of the gravitational force exerted by Mars on a 80 kg human standing on the surface of Mars. (The ma
andrew11 [14]

Answer:

a) F=1.044\times 10^9\ N

b)F'=1.044\times 10^9\ N

c) F_p=1.0672\times10^{-7}\ N

d) Treat the humans as though they were points or uniform-density spheres.

Explanation:

Given:

  • mass of Mars, M=6.4\times 10^{23}\ kg
  • radius of the Mars, r=3.4\times 10^{6}\ m
  • mass of human, m=80\ kg

a)

Gravitation force exerted by the Mars on the human body:

F=G.\frac{M.m}{r^2}

where:

G=6.67 \times 10^{-11}\ m^3.kg^{-1}.s^{-2} = gravitational constant

F=6.67\times10^{-11}\times \frac{6.4\times 10^{23}\times 80}{(3.4\times 10^{6})^2}

F=1.044\times 10^9\ N

b)

The magnitude of the gravitational force exerted by the human on Mars is equal to the force by the Mars on human.

F'=F

F'=1.044\times 10^9\ N

c)

When a similar person of the same mass is standing at a distance of 4 meters:

F_p=6.67\times10^{-11}\times \frac{80\times 80}{4}

F_p=1.0672\times10^{-7}\ N

d)

The gravitational constant is a universal value and it remains constant in the Universe and does not depends on the size of the mass.

  • Yes, we have to treat Mars as spherically symmetric so that its center of mass is at its geometric center.
  • Yes, we also have to ignore the effect of sun, but as asked in the question we have to calculate the gravitational force only due to one body on another specific body which does not brings sun into picture of the consideration.
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