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9966 [12]
3 years ago
11

Kinetic energy is the energy of an object in motion. Potential energy is the energy associated with an object

Physics
1 answer:
Charra [1.4K]3 years ago
4 0
True!!!!!!!!!!!!!!!!!!!!!!
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Four people are spaced at different distances from where a dog is barking. The barking will sound the loudest to the person who
Volgvan

Answer:

Closest to the dog.

Explanation:

Sounds are louder the closer you are to them.

6 0
3 years ago
A force of 200N due South and another force of 300N due East each act on an object simultaneously.
dangina [55]

Answer:

a) 500

b)-500, north west

Explanation:

a) sum of F= F1+F2= 200+300= 500

b) sum of forces=0

so 200+300-500+0

4 0
2 years ago
What is the equivalent unit to a newton?​
allsm [11]
My science teacher said that there is no equivalent unit to a newton
6 0
3 years ago
Read 2 more answers
What is the mechanical advantage of the wheel and axle shown below?
BigorU [14]

The correct answer is A. 32.5

Mechanical advantage is the ratio of force that is input into a machine to the force output.

Mechanical advantage of a wheel and axle is calculated by dividing the radius of the wheel by that of the axle.

MA=R/r where R is the radius of the wheel and  r is the radius of the axle.

Substituting for the values in the question gives:

MA=26cm/0.8cm

    =32.5

6 0
3 years ago
Read 2 more answers
A steel beam of mass 1975 kg and length 3 m is attached to the wall with a pin that can rotate freely on its right side. A cable
Nuetrik [128]

Answer:

a) 29062.125 N·m

b) 0 N·m

c) Torque, due \ to \ tension =L\cdot Tsin\theta = \frac{M\cdot L\cdot g}{2}

d) T = 11186.02 N

Explanation:

We are given

Beam mass = 1975 kg

Beam length = 3 m

Cable angle = 60° above horizontal

a) We have the formula for torque given as follows;

Torque about the pin = Force × Perpendicular distance of force from pin

Where the force = Force due to gravity or weight, we have

Weight = Mass × Acceleration due to gravity = 1975 × 9.81 = 19374.75 N

Point of action of force = Midpoint for a uniform beam = length/2

∴ Point of action of force = 3/2 = 1.5 m

Torque due to gravity = 19374.75 N × 1.5 m = 29062.125 N·m

b) Torque about the pinned end due to the contact forces between the pin and the beam is given by the following relation;

Since the distance from pin to the contact forces between the pin and the beam is 0, the torque which is force multiplied by perpendicular distance is also 0 N·m

c) To find the expression for the tension force, T we find the sum of the moment forces about the pin as follows

Sum of moments about p is given as follows

∑M = 0 gives;

T·sin(θ) × L= M×L/2×g

Therefore torque due to tension is given by the following expression

Torque, due \ to \ tension =L\cdot Tsin\theta = \frac{M\cdot L\cdot g}{2}

d) Plugging in the values in the torque due to tension equation, we have;

3\times Tsin60 = \frac{1975\times 3\times 9.81}{2} = 29062.125

Therefore, we make the tension force, T the subject of the formula hence

T= \frac{29062.125}{3 \times sin(60)} = 11186.02 N

8 0
3 years ago
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