An object is moving initially with a velocity of 4.7 m/s . After 3.9 s the object's velocity is -2.1 m/s . What is the object's

Question

3 years ago

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An object is moving initially with a velocity of 4.7 m/s . After 3.9 s the object's velocity is -2.1 m/s . What is the object's

average acceleration during this time?
I believe that the vf is -2.1 m/s vi should be 4.7 m/s and the t should be 3.9s but its wrong..? #confused

Physics

1 answer:

IgorC [24] · Answer 1 · 2021-12-28T22:30:15+03:00

Answer: The acceleration of the object is 0.67m/s^2 west.

Explanation: Here we are given the initial velocity and final velocity as well as the time taken. Acceleration is the change in velocity per unit time, thus the equation becomes.

a=dv/t

a=vf-vi/t

a=-2.1-4.7/3.9

a= 0.66m/s^2 west