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Yakvenalex [24]
3 years ago
14

An object is moving initially with a velocity of 4.7 m/s . After 3.9 s the object's velocity is -2.1 m/s . What is the object's

average acceleration during this time?
I believe that the vf is -2.1 m/s vi should be 4.7 m/s and the t should be 3.9s but its wrong..? #confused
Physics
1 answer:
IgorC [24]3 years ago
8 0

Answer: The acceleration of the object is 0.67m/s^2 west.

Explanation: Here we are given the initial velocity and final velocity as well as the time taken. Acceleration is the change in velocity per unit time, thus the equation becomes.

a=dv/t

a=vf-vi/t

a=-2.1-4.7/3.9

a= 0.66m/s^2 west

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Answer:

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4 years ago
Helpp pleaseeeeee …..
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Answer:

300 cos 30 = 40 a + 40 * .2 * 10

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Check:

15 a + 15 * 10 * .2 = T    acceleration of 15 kg block (assuming a = 4.5)

T = 15 (4.5) + 30 = 97.5     force required to accelerate 15 kg block

260 - 97.5 = 162.5     net force on 25 kg block

162.5 = 4.5 (25) + 25 * 10 * .2

162.5 = 112.5 + 50 = 162.5

4.5 m/s^2 checks out as correct

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