An object is moving initially with a velocity of 4.7 m/s . After 3.9 s the object's velocity is -2.1 m/s . What is the object's
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Considering the Coulomb's Law, the magnitude of the Coulomb force is 3.1865 N.
<h3>Coulomb's Law</h3>Charged bodies experience a force of attraction or repulsion on approach.
From Coulomb's Law it is possible to predict what the electrostatic force of attraction or repulsion between two particles will be according to their electric charge and the distance between them.
From Coulomb's Law, the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them:
where:
- F is the electrical force of attraction or repulsion. It is measured in Newtons (N).
- Q and q are the values of the two point charges. They are measured in Coulombs (C).
- d is the value of the distance that separates them. It is measured in meters (m).
- K is a constant of proportionality called the Coulomb's law constant. It depends on the medium in which the charges are located. Specifically for vacuum k is approximately 9×10⁹
.
The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.
<h3>This case</h3>In this case, you know that:
- The two uncharged sphere are separated by the distance of d= 3.50 m
- The number of electrons are 1.30×10¹².
- Electrons is elementary charge and charges on both the sphere is same. The value of electron is 1.602×10⁻¹⁹ C. This is, Q=q=1.30×10¹²×1.602×10⁻¹⁹ C= 2.0826×10⁻⁷ C
Replacing in Coulomb's Law:
Solving:
<u><em>F= 3.1865 N</em></u>
Finally, the magnitude of the Coulomb force is 3.1865 N.
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The quantity with units of length only is
Explanation:
We have to combine the following constants:
- , Planck constant, with units
- G, the Newton's gravitational constant, with units
- , the speed of light, with units
The combination of these constant should have units of length only, so with meters (m).
First, we notice that has [kg] in its units, while G has
in its units, so in order to make the [kg] disappear, we have to multiply them and they should have same power, so:
Now we have to make the seconds, [s], disappear. We do that by dividing the new quantity by , so that the new units are:
We are almost done: now the quantity has units of an area, squared meters. Therefore, in order to make it have it units of length, we just take its square root:
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Answer:
16.63min
Explanation:
The question is about the period of the comet in its orbit.
To find the period you can use one of the Kepler's law:
T: period
G: Cavendish constant = 6.67*10^-11 Nm^2 kg^2
r: average distance = 1UA = 1.5*10^11m
M: mass of the sun = 1.99*10^30 kg
By replacing you obtain:
the comet takes around 16.63min