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Dimas [21]
3 years ago
14

Newton’s first law of motion was a giant leap forward in scientific thought during Newton’s time. Even today, the idea is someti

mes difficult at first for people to understand.
Which statement is the best example of an object and motion that would make it hard for people to believe Newton’s first law?
a. A rolling ball eventually slows down and comes to a stop.
b. A wagon must be pushed before it begins to move.
c. The heavier the load in a cart, the harder the cart is to turn.
d. A box does not move when pushed equally from opposite sides.
Physics
2 answers:
masha68 [24]3 years ago
6 0

Answer: B

Explanation:

Newton's first law it's law of inertia.

An object at rest will remain at rest (or an object in motion in a straight line at a constant velocity will remain that way) unless it is acted by an unbalanced force.

In A for the ball to slow down and stop, an external force (like friction with air or the floor) needs to be taken in consideration.

In B we can see how we need to make a force on the wagon to make it move.

In C we have an other Newton 's law, force equals mass times acceleration (2nd law)

In D we can see how it does not move because the forces on the box are balanced.

Zanzabum3 years ago
3 0

Answer: a. A rolling ball eventually slows down and comes to a stop.

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The difference between experimental technique and procedure
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A procedure is all the steps used to do an experiment in order. 
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<span>the procedure is all the steps of the experiment.</span>
4 0
4 years ago
active and passive secruity measures are employed to identify, detect, classify and analyze possible threats inside of which zon
Juli2301 [7.4K]

Answer:

Assessment zone

Explanation:

It is the assessment zone in various security zones where active and passive security measures are employed to identify, detect, classify and analyze possible threats inside the assessment zones.

8 0
3 years ago
Light propagate faster through medium “a” than medium “b”
dangina [55]

1) Medium "b" has more optical density

2) Light must hit the interface between the two mediums perpendicularly

Explanation:

1)

Refraction occurs when light propagates from a medium into a second medium.

The optical density of a medium is given by its index of refraction, which is defined as:

n=\frac{c}{v}

where

c is the speed of light in a vacuum

v is the speed of light in a medium

Higher index of refraction means higher optical density, and light propagater slower into a medium with higher optical density.

In this problem, light propagates faster through medium "a" than medium "b": this means that medium "a" has lower refractive index of medium "b", and so "b" has more optical density.

2)

We can answer this part by referring to Snell's law, which gives the relationship between the direction of the incident ray and of the refracted ray when light passes through the interface between two media:

n_1 sin \theta_1 = n_2 sin \theta_2

where

n_1, n_2 are the index of refraction of the two mediums

\theta_1, \theta_2 are the angle of incidence and of refraction (the angle that light makes with the normal to the surface in medium 1 and medium 2)

Here we want the direction of propagation of the light ray not to change: this means that it must be

sin \theta_1 = sin \theta_2 (1)

However, here we have two mediums "a" and "b" with different index of refraction, so

n_1\neq n_2

Therefore the only angle that can satisfy eq.(1) is

\theta_1 = \theta_2 = 0

So, the light must hit the surface perpendicular to the interface between the two mediums.

Learn more about refraction:

brainly.com/question/3183125

brainly.com/question/12370040

#LearnwithBrainly

3 0
3 years ago
The pressure of a gas changes from 120 kPa. The volume changes from 45 L to 40 L. If the initial temperature is 81 c, what is th
irina [24]

Explanation:

we are not given the pressure change, check yhe question please

7 0
3 years ago
An object travels at a speed of 7500 cm/sec . how far will it travel in kilometers in one day
DiKsa [7]

Answer:

6480 km

Explanation:

The speed of the object is

v = 7500 cm/sec

We need to convert centimetres into kilometers and seconds into days. We have:

1 cm = 1\cdot 10^5 km

1 s = \frac{1}{60\cdot 60 \cdot 24}d

Using these conversion factors, we find:

v=7500 \frac{cm}{s} \cdot 1\cdot 10^{-5} \frac{km}{cm}\cdot (24)(60)(60) \frac{s}{d}=6480 km

3 0
3 years ago
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