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kolbaska11 [484]
3 years ago
11

Pls help me with this one :)) ​

Physics
1 answer:
zalisa [80]3 years ago
8 0

Answer:

Row A is correct

Explanation:

both conduction and convection require mass to complete any heat transfer. A vacuum contains no mass

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Which of the following statements is most closely associated with Einstein's general theory of relativity?
Fudgin [204]
The answer is the first one. That's because the general theory of relativity is the thing experiencing whatever is experiencing relative to something else. The second answer is just plain wrong. The third answer is just a constant, and doesn't relate to experiencing anything. And the fourth answer is a force between two objects, and it has no second comparison. The first answer is how a subject experiences two different things.
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3 years ago
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If u walk to school at a speed of 1.2 m/s and it takes you 18 min to reach the school, what is the distance from your home to th
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Answer:

21.6m

Explanation:

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=1.2m/s×18min

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a lump of putty and a rubber ball have equal mass. both are thrown with equal speed against a wall. the putty sticks to the wall
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The bouncy ball experiences the greater momentum change.

To understand why, you need to remember that momentum is actually
a vector quantity ... it has a size AND it has a direction too.

The putty and the ball have the same mass, and you throw them
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they both have the same momentum.
Call it " M in the direction toward the wall ".

After they both hit the wall:

-- The putty has zero momentum.
    Its momentum changed by an amount of  M .

-- The ball has momentum of " M in the direction away from the wall ".
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3 years ago
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What kind of light sources might be considered natural sources and which of them are artificial
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Answer:

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4 0
2 years ago
A sled of mass 15 kg slides across the ground with a friction force of 80.85 N. What is k between the sled and the ground?
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The expression for the frictional force between the sled and the ground is:
F=k m g
where k is the coefficient of friction, m is the mass of the object and g=9.81 m/s^2 is the gravitational acceleration.

The friction force in our problem is F=80.85 N. The mass of the object is m=15 kg. Re-arranging the formula, we can find the value of k:
k= \frac{F}{mg}= \frac{80.85 N}{(15 kg)(9.81 m/s^2)}=0.55
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3 years ago
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