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OlgaM077 [116]
3 years ago
8

FLUKE

Physics
1 answer:
Thepotemich [5.8K]3 years ago
3 0

Answer:

cant understand anything

Explanation:

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raketka [301]
<span>action is the one car hitting the other, reaction is the other car being pushed away</span>
7 0
3 years ago
An object is thrown upward with some velocity. If the object rises 77.5 m above the point of release, (a) how fast was the objec
jolli1 [7]

Answer:

v_o=39\ m/s\\t_m=4\ s

Explanation:

<u>Vertical Launch Upwards</u>

In a vertical launch upwards, an object is launched vertically up from a height H without taking into consideration any kind of friction with the air.

If vo is the initial speed and g is the acceleration of gravity, the maximum height reached by the object is given by:

\displaystyle h_m=H+\frac{v_o^2}{2g}

The object referred to in the question is thrown from a height H=0 and the maximum height is hm=77.5 m.

(a)

To find the initial speed we solve for vo:

\displaystyle v_o=\sqrt{2gh_m}

v_o=\sqrt{2\cdot 9.8\cdot 77.5}

v_o=39\ m/s

(b)

The maximum time or the time taken by the object to reach its highest  point is calculated as follows:

\displaystyle t_m=\frac{v_o}{g}

\displaystyle t_m=\frac{39}{9.8}

t_m=4\ s

7 0
2 years ago
3x/y=6g/b solve for x
lora16 [44]
So looking at the problem, you are going to want to start by finding a common denominator (1) in this case: yb, and combining like terms (2). You are then going to want to multiply both sides by (yb) as the reciprocal to the fractions (3).
1)  3x    6g
     ---- = ---
     y       b

2)  3xb    6gy
     ------ = -----   
     yb       yb

3)       3xb    6gy
  (yb) ------ = -----  
          yb       yb
which becomes: 3xb = 6gy

So after this, things become much more simple, as all you have to do is isolate the (x), which can be done by dividing the entire equation by (3b).

3xb   6gy
----- = -----
3b      3b

where you will then find your answer of:
      2gy
x = -----       (simplified by the GCM of 3)
       b
5 0
3 years ago
A 1,200-watt water heater is plugged into a 120-volt outlet and used for 1.5 hours. How much current runs through the water heat
stiv31 [10]
Current = power/voltage = 1200w/120v = 10 amperes. Constantly. Whenever the heater is turned on and heating.
4 0
3 years ago
Read 2 more answers
A student has a weight of 655 N. While riding a roller coaster they seem to weigh 1.96x 103 N at the bottom of a dip that has a
Nadya [2.5K]

Answer:

The speed of the roller coaster at this point is 18.74 m/s.

Explanation:

Given that,

Weight of the student, W = 655 kg

Weight of the roller coaster, F=1.96\times 10^3\ N

Radius of the roller coaster, r = 18 m

At the bottom of the loop, the weight of the roller coaster us given by :

F=W+\dfrac{mv^2}{r}

If m is the mass of the roller coaster,

W=mg

m=\dfrac{W}{g}

m=\dfrac{655}{9.8}

m = 66.83 kg

So,

F=W+\dfrac{mv^2}{r}

v=\sqrt{\dfrac{(F-W)r}{m}}

v=\sqrt{\dfrac{(1.96\times 10^3-655)\times 18}{66.83}}

v = 18.74 m/s

So, the speed of the roller coaster at this point is 18.74 m/s. Hence, this is the required solution.

4 0
3 years ago
Read 2 more answers
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