<span>action is the one car hitting the other, reaction is the other car being pushed away</span>
Answer:

Explanation:
<u>Vertical Launch Upwards</u>
In a vertical launch upwards, an object is launched vertically up from a height H without taking into consideration any kind of friction with the air.
If vo is the initial speed and g is the acceleration of gravity, the maximum height reached by the object is given by:

The object referred to in the question is thrown from a height H=0 and the maximum height is hm=77.5 m.
(a)
To find the initial speed we solve for vo:



(b)
The maximum time or the time taken by the object to reach its highest point is calculated as follows:



So looking at the problem, you are going to want to start by finding a common denominator (1) in this case: yb, and combining like terms (2). You are then going to want to multiply both sides by (yb) as the reciprocal to the fractions (3).
1) 3x 6g
---- = ---
y b
2) 3xb 6gy
------ = -----
yb yb
3) 3xb 6gy
(yb) ------ = -----
yb yb
which becomes: 3xb = 6gy
So after this, things become much more simple, as all you have to do is isolate the (x), which can be done by dividing the entire equation by (3b).
3xb 6gy
----- = -----
3b 3b
where you will then find your answer of:
2gy
x = ----- (simplified by the GCM of 3)
b
Current = power/voltage = 1200w/120v = 10 amperes. Constantly. Whenever the heater is turned on and heating.
Answer:
The speed of the roller coaster at this point is 18.74 m/s.
Explanation:
Given that,
Weight of the student, W = 655 kg
Weight of the roller coaster, 
Radius of the roller coaster, r = 18 m
At the bottom of the loop, the weight of the roller coaster us given by :

If m is the mass of the roller coaster,



m = 66.83 kg
So,



v = 18.74 m/s
So, the speed of the roller coaster at this point is 18.74 m/s. Hence, this is the required solution.