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OlgaM077 [116]
3 years ago
8

FLUKE

Physics
1 answer:
Thepotemich [5.8K]3 years ago
3 0

Answer:

cant understand anything

Explanation:

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A sphere of radius R contains charge Q spread uniformly throughout its volume. Find an expression for the electrostatic energy c
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Answer:

E = \frac{3kQ^2}{5R}

Explanation:

Let the sphere is uniformly charge to radius "r" and due to this charged sphere the electric potential on its surface is given as

V = \frac{kq}{r}

now we can say that

q = \frac{Q}{\frac{4}{3}\pi R^3} (\frac{4}{3}\pi r^3)

q = \frac{Qr^3}{R^3}

now electric potential is given as

V = \frac{k\frac{Qr^3}{R^3}}{r}

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now work done to bring a small charge from infinite to the surface of this sphere is given as

dW = V dq

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here we know that

dq = \frac{3Qr^2dr}{R^3}

now the total energy of the sphere is given as

E = \int dW

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E = \frac{3kQ^2}{R^6} (\frac{R^5}{5} - 0)

E = \frac{3kQ^2}{5R}

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3 years ago
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