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3 years ago

7

The question is how does the heat move through the space between the sun and earth? Match the heat transfer mechanism in space a

nd on earth with the correct discription.
PLEASE HELP IM RUNNING OUT OF TIME

1 answer:

Neporo4naja [7]3 years ago

7 0

Heat goes from sun to earth by way of electromagnetic radiation ... infrared is pretty warm stuff.

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Your friend, who is in a field 100 meters away from you, kicks a ball towards you with an initial velocity of 16 m/s. Assuming t

LekaFEV [45]

Answer:

Time, t = 5.355 seconds

Explanation:

Given the following data;

Distance = 100 m

Initial velocity = 16 m/s

Deceleration = 1 m/s²

To find the time, we would use the second equation of motion;

But since the ball is decelerating, it's acceleration would be negative.

S = ut + ½at²

Where;

S represents the displacement or height measured in meters.

u represents the initial velocity measured in meters per seconds.

t represents the time measured in seconds.

a represents acceleration measured in meters per seconds square.

Substituting into the equation, we have;

100 = 16t - 0.5t²

200 = 32t - t²

t² + 32t - 200 = 0

Solving the quadratic equation using the quadratic formula;

The quadratic equation formula is;

$x = \frac {-b \; \pm \sqrt {b^{2} - 4ac}}{2a}$

Substituting into the equation, we have;

$x = \frac {-32 \; \pm \sqrt {32^{2} - 4*1*(-200)}}{2*1}$

$x = \frac {-32\pm \sqrt {1024 - (-800)}}{2}$

$x = \frac {-32 \pm \sqrt {1024 + 800}}{2}$

$x = \frac {-32 \pm \sqrt {1824}}{2}$

$x = \frac {-32 \pm 42.71}{2}$

$x_{1} = \frac {-32 + 42.71}{2}$

$x_{1} = \frac {10.71}{2}$

x1 = 5.355

We do not need the negative value of x, so we proceed.

Therefore, time = 5.355 seconds

3 0

2 years ago

What is 6,000 in scientific notation

Lostsunrise [7]

6,000 in scientific notation is 6 x 10^3.

6 x 10^3 = 6,000

Hope this helps ! <3

3 0

2 years ago

A Cessna aircraft has a liftoff speed of 120 km/h What minimum constant acceleration does the aircraft require to be airborne af

Lady_Fox [76]

Answer:

<h3>2.3125m/s²</h3>

Explanation:

Using the equation of motion v² = u²+2aS

v is the final velocity = 120km/hr

120km/hr = 120 * 1000/1 * 3600 = 33.3m/s

u is the initial velocity = 0m/s

a is the acceleration

S is the distance covered = 240m

On substituting the given parameters

33.3² = 0²+2a(240)

33.3² = 480a

1110 = 480a

a = 1110/480

a = 2.3125m/s²

Hence the minimum constant acceleration that the aircraft require to be airborne after a takeoff run of 240 m is 2.3125m/s²

4 0

3 years ago

Help, im not sure how to do this at all

antiseptic1488 [7]

Answer:

60 m

Explanation:

The boat has two separate motions:

1- A motion due north, with constant speed of 10 m/s

1- A motion due east, due to the current, at speed of 2 m/s

We know that the river is 300 m wide, so we can consider first motion 1) to find how much does it take for the boat to cross the river:

$t=\frac{d}{v}=\frac{300 m}{10 m/s}=30s$

Now we can find how far downstream the boat moved by calculating the distance that the boat covered moving east during this time interval:

$d'=vt=(2 m/s)(30 s)=60 m$

5 0

2 years ago

Taya2010 [7]

<span>c. contains different kind of matter</span>

3 0

3 years ago