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Setler79 [48]
3 years ago
14

Enter the division problem 15 ÷11 as a fraction.

Mathematics
2 answers:
Evgen [1.6K]3 years ago
7 0

Answer: 15/11

Step-by-step explanation:

kari74 [83]3 years ago
3 0

Answer:

15 ÷ 11 as a fraction is 15/11. As a mixed number it is 1 4/11.

Step-by-step explanation:

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45?

9 marbles x 5 (four of her friends plus jake)

Step-by-step explanation:

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3 years ago
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Which of the following statements must be true about this diagram?<br> Check all that apply.
Alik [6]

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i would go for a and c

Step-by-step explanation:

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2 years ago
A and B are two events.
Vesna [10]
In order to determine if the events are independent or not we need to find the conditional probabilities.

The conditional probability of event A, given event B is denoted as P(A|B)

P(A|B)= \frac{P(A*B)}{P(B)}

P(A*B) indicates P(A and B)

Using the values, we get:

P(A|B)= \frac{0.28}{0.8}=0.35

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Therefore, the correct option is the second one.
2. A and B are not independent events because P(A∣∣B)≠P(A)
5 0
3 years ago
Read 2 more answers
Solve the following for x
levacccp [35]

Answer:

x = 9

Step-by-step explanation:

50+80+(6x-4)=180 (ANGLE SUM PROPERTY)

130 +(6x-4)=180

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4 0
3 years ago
A fluid moves through a tube of length 1 meter and radius r=0.006±0.00025 meters under a pressure p=4⋅105±2000 pascals, at a rat
iris [78.8K]

Answer:

Maximum error for viscosity is 17.14%

Step-by-step explanation:

We know that everything is changing with respect to the time, "r" is changing with respect to the time, and also "p" just "v" will not change with the time according to the information given, so we can find the implicit derivative with respect to the time, and since

n = (\frac{\pi}{8}) (\frac{pr^4}{v})\\

The implicit derivative with respect to the time would be

\frac{dn}{dt}  = \frac{\pi}{8} ( \frac{r^4}{v} \frac{dp}{dt}  + \frac{4pr^3}{v}\frac{dr}{dt} )

If we multiply everything by    dt   we get  

dn  = \frac{\pi}{8} ( \frac{r^4}{v} dp  + \frac{4pr^3}{v}  dr})

Remember that  the error is given by   \frac{dn}{n}   therefore doing some algebra we get that

\frac{dn}{n}  =    4 \frac{dr}{r}  +  \frac{dp}{p}

Since,    r = 0.006   ,   dr = 0.00025 ,  p = 4*105   ,   dp = 2000  we get that

\frac{dn}{n} = 0.1714

Which means that  the maximum error for viscosity is 17.14%.  

5 0
3 years ago
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