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kramer
3 years ago
9

A spacecraft is traveling in interplanetary space at a constant velocity. What is the estimated distance traveled by the spacecr

aft in 9.50 seconds?
Physics
2 answers:
Rus_ich [418]3 years ago
5 0
It's 9.5 times the magnitude of the velocity.
forsale [732]3 years ago
4 0
<span> Then distance traveled = speed * time.
</span> <span>Distance = v * 9.5
</span>hope this helps
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The average intensity of sunlight at the top of the earth's atmosphere in 1390 w/m2. what is the maximum energy that a 34-m x 46
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Panel surface area =34m×46m=1,564m^2
total power =1564m^2×1390w/m^2
=2173960watts
now you must calculate total energy.
Energy = power×Time
However time must be in seconds so we multiply 2hrs×60min×60s=7200seconds
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3 years ago
What phylum do animals with backbones belong to?
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They belong to the kingdom of Chordata
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3 years ago
A conducting rod is moving through a magnetic field, as in the drawing. The magnetic field strength is 0.65 T, and the speed of
Contact [7]

Explanation:

The given data is as follows.

 Magnetic field strength (B) = 0.65 T

 Speed (v) = 2.3 m/s

 Induced emf (E) = ?

Formula for emf induced at the ends of the rod of length L which is moving with a speed of v is as follows.

                              E = BvL

Putting the given values into the formula as follows.

          E_{1} = BvL

                      = 0.65 T \times 2.3 m/s \times L

                      = 1.495 L .............. (1)

When magnetic field is changed to B_{2} = 0.48 T

Now, we assume that the speed be v_{2} to get the emf E_{2} = E_{1}.

Then,    0.48 T \times v_{2} \times L = 0.65 T \times 2.3 m/s \times L

                  v_{2} = 3.11 m/s

Therefore, we can conclude that the speed v of the rod be adjusted to reestablish the emf induced between the ends of the rod at its initial value is 3.11 m/s.

6 0
3 years ago
Gauss's law combines the electric field over a surface with the area of the surface. From Coulomb's law we know that the electri
Romashka-Z-Leto [24]

The change in surface area of Gaussian surface with radius (r) is 8πr.

<h3>Electric field from Coulomb's law</h3>

The electric field experienced by a charge is calculated as follows;

E = \frac{Q}{4\pi \varepsilon_o r^2}

where;

  • E is the electric field
  • Q is the charge
  • r is the radius

The electric field reduces by a factor of \frac{1}{r^2}

<h3>Surface area of a Gaussian surface;</h3>

The surface area of a sphere is given as;

A = 4\pi r^2

<h3>Change in area with r</h3>

\frac{dA}{dr} = 8\pi r

Thus, the change in surface area of Gaussian surface with radius (r) is 8πr.

Learn more about area of Gaussian surfaces here: brainly.com/question/17060446

7 0
2 years ago
Un atleta tiene en un instante dado una velocidad de 4 m/s. Si a partir de ese instante y durante 2 s adquiere un MRUA con una a
kolbaska11 [484]

Answer:

Velocidad final, V = 8 m/s

Explanation:

Dados los siguientes datos;

Velocidad inicial, u = 4 m/s

Aceleración, a = 2 m/s²

Tiempo, t = 2 segundos

Para encontrar la velocidad final (v), usaríamos la primera ecuación de movimiento;

V = u + at

Sustituyendo en la fórmula, tenemos;

V = 4 + 2*2

V = 4 + 4

Velocidad final, V = 8 m/s

6 0
3 years ago
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