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hammer [34]
2 years ago
14

calculate the ratio of [sodium acetate] to [acetic acid] in a buffer solution that has a ph of 4.25. the ka for acetic acid at 2

5 °c is 1.7 × 10−5. please choose the correct answer from the following choices, and then select the submit answer button. answer choices
Chemistry
1 answer:
const2013 [10]2 years ago
5 0

The ratio of [sodium acetate] to [acetic acid] in a buffer solution is 0.30.

Henderson–Hasselbalch equation: pH = pKa + log(cs/ck)

pH = 4.25; pH of buffer solution

pKa = -log(1.7 × 10−5) = 4.77

4.25 = 4.77 + log(cs/ck)

log(cs/ck) =4.25 - 4.77 = -0.52

cs/ck = 10∧(-0.52) = 0.30; ratio of sodium acetate to acetic acid

A buffer can be defined as a substance that prevents the pH of a solution from changing by either releasing or absorbing H⁺ in a solution.

Buffer is a solution that can resist pH change upon the addition of an acidic or basic components and it is able to neutralize small amounts of added acid or base, pH of the solution is relatively stable.

More about sodium acetate: brainly.com/question/24671704

#SPJ4

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Answer:

All properties of matter are either physical or chemical properties and physical properties are either intensive or extensive. ... Physical properties can be measured without changing a substance's chemical identity. Chemical properties can be measured only by changing a substance's chemical identity.

Explanation:

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2 years ago
What electronic structure do most of the noble gases have in common
bulgar [2K]

Noble gases belong to group 18 of the periodic table. These elements are inert because they have their valence orbital shells as ‘full’ hence do not participate in reactions since they cannot share electrons. These elements have a pattern in their electron configuration. Their outer most orbital shells has 8 electrons (with the exception of 2 for helium).

3 0
3 years ago
25.0 mL of an LiOH solution were titrated with 29.15 mLof a 0.205 M H3PO4 solution to reach the equivalence point. What is the m
borishaifa [10]

Answer:

0.717 M LiOH

Explanation:

(Step 1)

Calculate the moles of H₃PO₄ using the molarity equation.

29.15 mL / 1,000 = 0.02915 L

Molarity = moles / volume (L)

0.205 M = moles / 0.02915 L

0.00598 = moles

(Step 2)

Convert moles H₃PO₄ to moles LiOH using the mole-to-mole ratio from reaction coefficients.

1 H₃PO₄ + 3 LiOH -----> Li₃PO₄ + 3 H₂O
^                ^

0.00598 moles H₃PO₄            3 moles LiOH
------------------------------------  x  --------------------------  =  0.0179 moles LiOH
                                                  1 mole H₃PO₄

(Step 3)

Calculate the molarity of LiOH using the molarity equation.

25.0 mL / 1,000 = 0.0250 L

Molarity = moles / volume (L)

Molarity = 0.0179 moles / 0.0250 L

Molarity = 0.717 M

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2 years ago
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Therefore, form the periodic table, we can see that aluminum has a atomic number of 13, which makes its electron arrangement be 2,8,3. So, in order to form a aluminum ion, an Al atom must lose 3 electrons. On the other hand, Chlorine has a atomic number of 17, which means it has the electron configuration of 2,8,7. It has to gain only 1 electron to have 8 outermost shell electron.

Thereofre, 3 Chlorine atom are required to gain all 3 electrons given out by just 1 aluminum ion.
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