Answer:
28.38 ml of H202
Explanation:
<u><em>Given data:</em></u>
the concentration of H2O2 = 3.0 % v/v (3ml / 100 ml of solution of H2O2
the volume of the bottle : 946 ml
<em><u>Formula: </u></em>
Percent by volume: volume of solute/volume of solution×100%
<em><u>Solution:</u></em>
= (3.0 mL/ 100 ml) × 946 mL
= 0.03 x 946 ml
= 28.38ml of H202
4 significant figures. Use a rule called the Atlantic-Pacific rule where if the period is absent (Atlantic), you would start counting the numbers from right to left. If the period is present (Pacific), then start counting the numbers from left to right. Since the period is present, start from 5 and there are 4 digits including 5.
Answer: The question is is not complete...here is the complete question.
Which of the following reagents should be used to convert 3-Hexyne to E-3-hexene
Option B.
Na, liquid NH3.
Explanation:
3-Hexyne to E-3-hexene can be converted with by using the reagent of Na, NH3 (birch reduction) and this can be done by hdrogenation of H2.
The reagents NaNH3 convert 3-Hexyne to E-3-hexene because it is a reducing agents that convert or has the ability to reduce alkynes to trans alkenes.
3 Hexyne is an alkynes and it is converted to E- 3 hexene Na and NH3.
Answer:
7.44 C is the answer of the question.
Explanation:
Answer:
Before you use log you have to multiply the answer of 8.66 mol by 6.02⋅1023 by 3 because the answer of 8.66 mol by 6.02⋅1023 gives you the number of ammonia molecules and in each molecules there are 3 hydrogen atoms present.
Explanation: