Answer:
All properties of matter are either physical or chemical properties and physical properties are either intensive or extensive. ... Physical properties can be measured without changing a substance's chemical identity. Chemical properties can be measured only by changing a substance's chemical identity.
Explanation:
Noble gases belong to group 18 of the periodic table. These elements are inert because they have their valence orbital shells as ‘full’ hence do not participate in reactions since they cannot share electrons. These elements have a pattern in their electron configuration. Their outer most orbital shells has 8 electrons (with the exception of 2 for helium).
Answer:
0.717 M LiOH
Explanation:
(Step 1)
Calculate the moles of H₃PO₄ using the molarity equation.
29.15 mL / 1,000 = 0.02915 L
Molarity = moles / volume (L)
0.205 M = moles / 0.02915 L
0.00598 = moles
(Step 2)
Convert moles H₃PO₄ to moles LiOH using the mole-to-mole ratio from reaction coefficients.
1 H₃PO₄ + 3 LiOH -----> Li₃PO₄ + 3 H₂O
^ ^
0.00598 moles H₃PO₄ 3 moles LiOH
------------------------------------ x -------------------------- = 0.0179 moles LiOH
1 mole H₃PO₄
(Step 3)
Calculate the molarity of LiOH using the molarity equation.
25.0 mL / 1,000 = 0.0250 L
Molarity = moles / volume (L)
Molarity = 0.0179 moles / 0.0250 L
Molarity = 0.717 M
3 Chlorine ions are required to bond with one aluminum ion.
In ionic bonds, metals atoms loses all its outermost shell electrons to form a cation. While, non metal atoms gains however many electrons in order to make its outermost electron shell be 8 (or 2 if there's only one shell).
Therefore, form the periodic table, we can see that aluminum has a atomic number of 13, which makes its electron arrangement be 2,8,3. So, in order to form a aluminum ion, an Al atom must lose 3 electrons. On the other hand, Chlorine has a atomic number of 17, which means it has the electron configuration of 2,8,7. It has to gain only 1 electron to have 8 outermost shell electron.
Thereofre, 3 Chlorine atom are required to gain all 3 electrons given out by just 1 aluminum ion.
V2O5 is the formula. Vanadium has a charge of +5 and oxygen is -2, so to make them equal, you need to double the vanadium charge and multiply the oxygen charge by 5