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Zolol [24]
3 years ago
9

Aluminium reacts with sulfuric acid to form aluminium sulfate and hydrogen. What is the volume of

Chemistry
1 answer:
VashaNatasha [74]3 years ago
7 0

Answer:

2al + 3h2so4 =  > al2(so4)3 + 3h2 \\ eqvt \\  =  >  \frac{5.4}{27}  = >   \frac{5 \times 50}{1000}  \\ .2 \: mol =  > .25 \: mol \\  \\ so \: .25 \: is \: limiting \: reagent \\ according \: to \: ideal \: gas \: equation \\ pv = nrt \\ v =  \frac{nrt}{p}  \\ v =  \frac{.25 \times .082 \times 300}{1}  \\  =  \frac{1}{4}  \times 8.2 \times 3  \\  = 2.05 \times 3 \\  = 6.15litre \\ thank \: you

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Afina-wow [57]

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First we have to calculate the mole of PbCrO_4.

\text{Moles of }PbCrO_4=\frac{\text{Mass of }PbCrO_4}{\text{Molar mass of }PbCrO_4}=\frac{0.162g}{323g/mole}=0.005mole

Now we have to calculate the moles of PbSO_4.

The balanced chemical reaction will be,

PbSO_4+Na_2CrO_4\rightarrow PbCrO_4+Na_2SO_4[tex]From the balanced chemical reaction, we conclude thatAs, 1 mole of [tex]PbCrO_4 produced from 1 mole of PbSO_4

So, 0.005 mole of PbCrO_4 produced from 0.005 mole of PbSO_4

Now we have to calculate the mass of PbSO_4

\text{Mass of }PbSO_4=\text{Moles of }PbSO_4\times \text{Molar mass of }PbSO_4

\text{Mass of }PbSO_4=0.005mole\times 303g/mole=1.515g

Therefore, the mass of PbSO_4 needed are, 1.515 grams.

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3 years ago
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