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Zolol [24]
3 years ago
9

Aluminium reacts with sulfuric acid to form aluminium sulfate and hydrogen. What is the volume of

Chemistry
1 answer:
VashaNatasha [74]3 years ago
7 0

Answer:

2al + 3h2so4 =  > al2(so4)3 + 3h2 \\ eqvt \\  =  >  \frac{5.4}{27}  = >   \frac{5 \times 50}{1000}  \\ .2 \: mol =  > .25 \: mol \\  \\ so \: .25 \: is \: limiting \: reagent \\ according \: to \: ideal \: gas \: equation \\ pv = nrt \\ v =  \frac{nrt}{p}  \\ v =  \frac{.25 \times .082 \times 300}{1}  \\  =  \frac{1}{4}  \times 8.2 \times 3  \\  = 2.05 \times 3 \\  = 6.15litre \\ thank \: you

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Answer:

The maximum mass of carbon dioxide that could be produced by the chemical reaction is 70.6gCO_{2}

Explanation:

1. Write down the balanced chemical reaction:

2C_{6}H_{14}_{(l)}+19O_{2}_{(g)}=12CO_{2}_{(g)}+14H_{2}O_{(g)}

2. Find the limiting reagent:

- First calculate the number of moles of hexane and oxygen with the mass given by the problem.

For the hexane:

70.0gC_{6}H_{14}*\frac{1molC_{6}H_{14}}{86.2gC_{6}H_{14}}=0.81molesC_{6}H_{14}

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81.3gO_{2}*\frac{1molO_{2}}{32.0gO_{2}}=2.54molesO_{2}

- Then divide the number of moles between the stoichiometric coefficient:

For the hexane:

\frac{0.81}{2}=0.41

For the oxygen:

\frac{2.54}{19}=0.13

- As the fraction for the oxygen is the smallest, the oxygen is the limiting reagent.

3. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction:

The calculations must be done with the limiting reagent, that is the oxygen.

81.3gO_{2}*\frac{1molO_{2}}{32gO_{2}}*\frac{12molesCO_{2}}{19molesO_{2}}*\frac{44.0gCO_{2}}{1molCO_{2}}=70.6gCO_{2}

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