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svetoff [14.1K]

3 years ago

14

What is the measure of angle A?

2 answers:

DochEvi [55]3 years ago

6 0

Answer:

60

Step-by-step explanation:

60 plus 60 plus 60 is 180

has to add up to 180

olasank [31]3 years ago

5 0

Answer:

60°

Step-by-step explanation:

as we can see that the triangle is equal , and the measure of an angle is 180°

we can divide 180 by 3

180÷3

60

hope it helps,pls mark me as brainliest

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3 years ago

Do you tailgate the car in front of you? About 35% of all drivers will tailgate before passing, thinking they can make the car i

Vesna [10]

Answer:

(a) The histogram is shown below.

(b) E (X) = 4.2

(c) SD (X) = 2.73

Step-by-step explanation:

Let <em>X</em> = <em>r</em><em> </em>= a driver will tailgate the car in front of him before passing.

The probability that a driver will tailgate the car in front of him before passing is, P (X) = <em>p</em> = 0.35.

The sample selected is of size <em>n</em> = 12.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 12 and <em>p</em> = 0.35.

The probability function of a binomial random variable is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x}$

(a)

For <em>X</em> = 0 the probability is:

$P(X=0)={12\choose 0}(0.35)^{0}(1-0.35)^{12-0}=0.006$

For <em>X</em> = 1 the probability is:

$P(X=1)={12\choose 1}(0.35)^{1}(1-0.35)^{12-1}=0.037$

For <em>X</em> = 2 the probability is:

$P(X=2)={12\choose 2}(0.35)^{2}(1-0.35)^{12-2}=0.109$

Similarly the remaining probabilities will be computed.

The probability distribution table is shown below.

The histogram is also shown below.

(b)

The expected value of a Binomial distribution is:

$E(X)=np$

The expected number of vehicles out of 12 that will tailgate is:

$E(X)=np=12\times0.35=4.2$

Thus, the expected number of vehicles out of 12 that will tailgate is 4.2.

(c)

The standard deviation of a Binomial distribution is:

$SD(X)=np(1-p)$

The standard deviation of vehicles out of 12 that will tailgate is:

$SD(X)=np(1-p)=12\times0.35\times(1-0.35)=2.73\\$

Thus, the standard deviation of vehicles out of 12 that will tailgate is 2.73.

4 0

3 years ago