(a) The time for the capacitor to loose half its charge is 2.2 ms.
(b) The time for the capacitor to loose half its energy is 1.59 ms.
<h3>
Time taken to loose half of its charge</h3>
q(t) = q₀e-^(t/RC)
q(t)/q₀ = e-^(t/RC)
0.5q₀/q₀ = e-^(t/RC)
0.5 = e-^(t/RC)
1/2 = e-^(t/RC)
t/RC = ln(2)
t = RC x ln(2)
t = (12 x 10⁻⁶ x 265) x ln(2)
t = 2.2 x 10⁻³ s
t = 2.2 ms
<h3>
Time taken to loose half of its stored energy</h3>
U(t) = Ue-^(t/RC)
U = ¹/₂Q²/C
(Ue-^(t/RC))²/2C = Q₀²/2Ce
e^(2t/RC) = e
2t/RC = 1
t = RC/2
t = (265 x 12 x 10⁻⁶)/2
t = 1.59 x 10⁻³ s
t = 1.59 ms
Thus, the time for the capacitor to loose half its charge is 2.2 ms and the time for the capacitor to loose half its energy is 1.59 ms.
Learn more about energy stored in capacitor here: brainly.com/question/14811408
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Answer:
speed
Explanation:
Given: an incomplete sentence
To fill: the blank
Solution:
Speed is not a vector quantity but a scalar quantity as it has magnitude but no direction.
Speed = Distance ÷ Time
You can calculate an <u>average</u> speed if you know both the total distance and the total time of the trip.
Average speed = Total distance ÷ Total time
Answer:
From the formular of magnetic force:
• F » magnetic force, B » magnetic flux density, I » current, l » length [ assume l = 1 m ]
Answer:
The radius = 170.21 m
Explanation:
The given data are : -
The centripetal acceleration of a car = 9.40 m/s².
Speed of a car = 40.0 m/s .
We have to calculate the radius ( r ) of of curve.
The centripetal acceleration ( a ) is given by
a = 
r = 
= 
= 
= 170.21 m
