Answer: M = 1797.75 kg
Explanation:
given parameters are;
speed V = 26.7 M/S.
momentum P = 4.8×10^4 KGM/S.
What was the mass of the V. A-3?
Momentum P is the product of mass and velocity. That is, P = MV
Substitute V and P into the formula
4.8×10^4 = 26.7 × M
Make M the subject of formula
M = 4.8×10^4/ 26.7
M = 1797.75 kg
Therefore, the mass of the V. A-3 was 1797.75 kg
Answer:
A) 37 m
Explanation:
The car is moving of uniformly accelerated motion, so the distance it covers can be calculated by using the following SUVAT equation:
(1)
where
v = 0 m/s is the final velocity of the car
u = 24 m/s is the initial velocity
a is the acceleration
d is the length of the skid
We need to find the acceleration first. We know that the force responsible for the (de)celeration is the force of friction, so:
where
m = 1000 kg is the mass of the car
is the coefficient of friction
a is the deceleration of the car
g = 9.8 m/s^2 is the acceleration due to gravity
The negative sign is due to the fact that the force of friction is against the motion of the car, so the sign of the acceleration will be negative because the car is slowing down. From this equation, we find:
And we can substitute it into eq.(1) to find d:
Hydrogen has one electron in its outermost shell, while fluorine has seven electron in its outermost shell, hence both hydrogen and fluorine needs a single electron to complete its outermost shell.
That's why there is a single bond between hydrogen and fluorine.
Hence both hydrogen and fluorine share one electron with each other, so option "A" is correct.
W = mg
Weight on Earth = 50 x 9.8
= 490 N
Weight on Mars = 50 x 3.7
= 185 N
<span>vf^2 = vi^2 + 2*a*d
---
vf = velocity final
vi = velocity initial
a = acceleration
d = distance
---
since the airplane is decelerating to zero, vf = 0
---
0 = 55*55 + 2*(-2.5)*d
d = (-55*55)/(2*(-2.5))
d = 605 meters
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