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scoundrel [369]
3 years ago
11

Two long thin wires carry currents of 2 A and 4 A out of the page. A magnetic force per meter of 5.0 × 10⁻⁴ ????/m acts on wire

2. What is the magnetic force per meter that acts on wire 1?
Physics
1 answer:
Ray Of Light [21]3 years ago
4 0

Answer:

Explanation:

Given

Current in two wires

I_1=2 A

I_2=4 A

Magnetic Force per unit length is given by

\frac{F}{l}=\frac{\mu _0I_1I_2}{2\pi r}

where \mu _0=space\ permittivity

r=radial distance between wires

F_{12}=5\times 10^{-4} N/m

Force on two wires will be equal in magnitudes but opposite in direction so Force on wire 1 duet o wire 2

F_{12}=5\times 10^{-4} N/m

                 

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What do we mean by the interstellar medium?
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3 0
3 years ago
A) A real object 4.0 cm high stands 30.0 cm in front of a converging lens of focal length 23 cm. Find the image distance, the im
vfiekz [6]

Explanation:

Given that,

Height of object = 4.0 cm

Distance of the object u= -30.0 cm

Focal length = 23 cm

We need to calculate the image distance

Using lens's formula

\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}

Where, u = object distance

v = image distance

f = focal length

Put the value into the formula

\dfrac{1}{v}-\dfrac{1}{-30}=\dfrac{1}{23}

\dfrac{1}{v}=\dfrac{1}{23}-\dfrac{1}{30}

\dfrac{1}{v}=\dfrac{7}{690}

v=98.57\ cm

We need to calculate the height of the image

Using formula of height

\dfrac{h'}{h}=\dfrac{-v}{u}

Where, h' = height of image

h = height of object

\dfrac{h'}{4}=\dfrac{-98.57}{-30}

h'=\dfrac{98.57\times4}{30}

h'=13.14\ cm

The image is real and inverted.

(b). Now, object distance u = 13.0 cm

We need to calculate the image distance

Using lens's formula

\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}

Put the value into the formula

\dfrac{1}{v}=\dfrac{1}{23}-\dfrac{1}{13.0}

\dfrac{1}{v}=-\dfrac{10}{299}

v=-29.9\ cm

We need to calculate the height of the image

\dfrac{h'}{4}=\dfrac{-(-29.9)}{-13.0}

h=-\dfrac{29.9\times4}{13.0}

h=-9.2\ cm

The image is virtual and erect.

Hence, This is required solution.

6 0
3 years ago
An ideal gas at 27°C is contained in a piston that ensures that its pressure will always be constant. Raising the tem- perature
zlopas [31]

Answer:

T = 600K

Explanation:

See attachment below.

7 0
4 years ago
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