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vaieri [72.5K]
3 years ago
12

Why is a device never 100% efficient? *

Physics
1 answer:
oksano4ka [1.4K]3 years ago
5 0
I think it’s c, friction
I’m not sure tho
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If a roller coaster train has a potential energy of 1,500 J and a kinetic energy of 500 J as it starts to travel downhill, what
user100 [1]
Total Mechanical Energy = Kinetic Energy + Potential Energy 
Here, K.E. = 500 J
P.E. = 1500 J

Substitute their values, 
E = 1500 + 500
E = 2000 J

In short, Your Answer would be 2000 Joules

Hope this helps!
8 0
4 years ago
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29.92 inches of mercury and 101,325 pascals are both equivalent to 1 atmosphere of pressure. Calculate the number of pascals equ
Anon25 [30]

The number of pascal equivalent to 1 inch of mercury is 3386.53 pascal

From the question given above, we were told that:

29.92 inches of mercury = 1 atm

101325 pascal = 1 atm

Thus,

29.92 inches of mercury = 101325 pascal

  • With the above information, we can obtain the number of pascal equivalent to 1 inch of mercury. This can be obtained as follow:

29.92 inches of mercury = 101325 pascal

Therefore,

1 inches of mercury = 101325 / 29.92

<h3>1 inches of mercury = 3386.53 pascal</h3>

Thus, the number of pascal equivalent to 1 inch of mercury is 3386.53 pascal

Learn more: brainly.com/question/12663234

6 0
3 years ago
Forces always act in pairs.<br><br> True<br> False
Anon25 [30]
Truer words were never written. Forces do indeed always act in pairs.
8 0
3 years ago
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A coach wants her team to have fun, win some games, and be a productive unit. What is the most important personality trait the c
konstantin123 [22]
Discipline or leadership................................
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3 years ago
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Two charged objects attract each other with a force of F. What happens to the force between them if one charge is doubled, the o
Ray Of Light [21]

Answer:

The force is increased by a factor of 96. (F1 = 96F)

Explanation:

Let the first charge be Q1

Let the second charge be Q2

Let the distance between their centers be r

The electrostatic force, F, between them is:

F = (k*Q1*Q2) / r²

If the first charge is doubled = 2Q1

If the second charge is tripled = 3Q2

The separation between their centers is reduced to ¼ = ¼r

The force between them becomes:

F1 = (k* 2Q1 * 3Q2) / (¼r)²

F1 = (6 * k * Q1 * Q2) / (r²/16)

F1 = 96(k * Q1 * Q2) /r²

F1 = 96F

The force is increased by a factor of 96.

3 0
3 years ago
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