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Tom [10]
4 years ago
5

What makes an atom neutral

Chemistry
1 answer:
lana66690 [7]4 years ago
5 0

Answer:

A normal atom has a neutral charge with equal numbers of positive and negative particles. That means an atom with a neutral charge is one where the number of electrons is equal to the atomic number. Ions are atoms with extra electrons or missing electrons.

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Write the acid-base reaction where hydrogen carbonate is the acid and water is the base.
koban [17]
HI

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6 0
3 years ago
A thin-walled sphere rolls along the floor. What is the ratio of its translational kinetic energy to its rotational kinetic ener
ICE Princess25 [194]

Explanation:

The kinetic energy of translation

E_1=\frac{1}{2}mv^2

m= mass v= linear velocity

The kinetic energy of rotation

E_2=\frac{1}{2}I\omega^2

I= MOI of the thin walled sphere =kmR^2

where ω= v/R= angular velocity

E_2=\frac{1}{2}kmR^2\frac{v}{R}^2

Then

\frac{E_1}{E_2} = \frac{0.5mv^2}{0.5kmR^2\frac{v}{R}^2 }

=1/k

solid sphere: k=0.4;   E1/E2 =1/0.4 = 2.5;  

 hollow sphere: k=2/3;   E1/E2 = 1.5

3 0
3 years ago
For a particular reaction, ΔH⁰ = − 46.7 kJ/mol and ΔS⁰ = − 123.8 J / (mol ⋅ K). Assuming these values change very little with te
PilotLPTM [1.2K]

Answer:

T = 377.2 K, Less than

Explanation:

The thermodynamic quantity used in predicting whether a reaction is spontaneous or not is the gibbs free energy.

It's relationship with ΔH⁰ and ΔS⁰ is given as;

ΔG° = ΔH° - TΔS°

Basically, a negative value of ΔG° means the reaction is spontaeneous.

To obtain the calculated vale of T,

ΔS° = ΔH°/T

T = ΔH° / ΔS°

T = 377.2 K

Let's calculate the value of ΔG° at that temperature.

ΔG° = ΔH° - TΔS°

ΔG° =  − 46700 - 377.2(− 123.8)

ΔG°  = 0 (approximately, values are due to the rounding off)

At ΔG°  = 0 the reaction is at equilibrium.

To find if the reaction is spontaneous at lower or hugher temperature than the calculated temperature, we would be substituting the value of T with a smaller (random) value and also a larger (random) value.

Larger T (390K)

ΔG° = ΔH° - TΔS°

ΔG° =  − 46700 - 390(− 123.8)

ΔG°  = - 46700 + 48,282

ΔG° = 1582 J/mol

Smaller T (350K)

ΔG° = ΔH° - TΔS°

ΔG° =  − 46700 - 350(− 123.8)

ΔG°  = - 46700 + 43330

ΔG° = -3370J/mol

This means the temperature would be lesser than the calculated value for it to be spontaneus.

8 0
3 years ago
Which of the substances in the chemical equation is a pure substance?
Anni [7]

Answer:

D. all of these

Explanation:

7 0
4 years ago
Read 2 more answers
A 2.16-g sample of an oxide of chromium contains 1.34 g of chromium. Calculate the simplest formula for the compound.
fomenos

Answer:

chromium:oxygen=1:2  

Explanation:

total mass=2.16g

mass of chromium=1.34g

mass of oxygen=2.16g-1.34g=0.82g

           chromium                                         oxygen

mass:1.34g                                                       0.82

RAM:52                                                            16

divide the mass with the RAM

   0.02577                                                           0.05125

divide by smallest number to find ratio

1                                                                             2

ratio of chromium to oxygen=1:2

8 0
4 years ago
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