All categories

3 years ago

Physical properties of alkaline metals

Chemistry

1 answer:

denis-greek [22]3 years ago

8 0

Answer:

shiny.

silvery-white.

somewhat reactive metals at standard temperature and pressure.

readily lose their two outermost electrons to form cations with a 2+ charge.

low densities.

low melting points.

low boiling points.

Explanation:

You might be interested in

An atom is the most __________ unit of living and nonliving things. (Help I will mark brainliest if ya help, and the first one t

ziro4ka [17]

The correct answer to your question is

Basic. it is the is the basic unit of non living things.

Hope this helps!

6 0

3 years ago

Read 2 more answers

In a chemical change, the substance that you end up with is the

elena55 [62]

The reactant is what you begin with.
The product is what you end up with (so the answer is B)

3 0

3 years ago

Read 2 more answers

Combine the two half-reactions that give the spontaneous cell reaction with the smallest E∘. Fe2+(aq)+2e−→Fe(s) E∘=−0.45V I2(s)+

Iteru [2.4K]

Answer: The spontaneous cell reaction having smallest $E^o$ is $I_2+Cu\rightarrow Cu^{2+}+2I^-$

Explanation:

We are given:

$E^o_{(Fe^{2+}/Fe)}=-0.45V\\E^o_{(I_2/I^-)}=0.54V\\E^o_{(Cu^{2+}/Cu)}=0.34V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, iodine will always undergo reduction reaction, then copper and then iron.

The equation used to calculate electrode potential of the cell is:

$E^o_{cell}=E^o_{oxidation}+E^o_{reduction}$

The combination of the cell reactions follows:

Case 1:

Here, iodine is getting reduced and iron is getting oxidized.

The cell equation follows:

$I_2(s)+Fe(s)\rightarrow Fe^{2+}(aq.)+2I^-(aq.)$

Oxidation half reaction: $Fe(s)\rightarrow Fe^{2+}(aq.)+2e^-$ $E^o_{oxidation}=0.45V$

Reduction half reaction: $I_2(s)+2e^-\rightarrow 2I_-(aq.)$ $E^o_{reduction}=0.54V$

$E^o_{cell}=0.45+0.54=0.99V$

Thus, this cell will not give the spontaneous cell reaction with smallest $E^o_{cell}$

Case 2:

Here, iodine is getting reduced and copper is getting oxidized.

The cell equation follows:

$I_2(s)+Cu(s)\rightarrow Cu^{2+}(aq.)+2I^-(aq.)$

Oxidation half reaction: $Cu(s)\rightarrow Cu^{2+}(aq.)+2e^-$ $E^o_{oxidation}=-0.34V$

Reduction half reaction: $I_2(s)+2e^-\rightarrow 2I_-(aq.)$ $E^o_{reduction}=0.54V$

$E^o_{cell}=-0.34+0.54=0.20V$

Thus, this cell will give the spontaneous cell reaction with smallest $E^o_{cell}$

Case 3:

Here, copper is getting reduced and iron is getting oxidized.

The cell equation follows:

$Cu^{2+}(aq.)+Fe(s)\rightarrow Fe^{2+}(aq.)+Cu(s)$

Oxidation half reaction: $Fe(s)\rightarrow Fe^{2+}(aq.)+2e^-$ $E^o_{oxidation}=0.45V$

Reduction half reaction: $Cu^{2+}(aq.)+2e^-\rightarrow Cu(s)$ $E^o_{reduction}=0.34V$

$E^o_{cell}=0.45+0.34=0.79V$

Thus, this cell will not give the spontaneous cell reaction with smallest $E^o_{cell}$

Hence, the spontaneous cell reaction having smallest $E^o$ is $I_2+Cu\rightarrow Cu^{2+}+2I^-$

7 0

3 years ago

In a survey that asked about alcohol use in high school students, which of

Nookie1986 [14]

Answer: B

Explanation: to have a control, and many samples to investigate and cover the differences and anseretics.

7 0

3 years ago

Read 2 more answers

Earth would fly off into space in a straight line if the ______________________________

ser-zykov [4K]

Answer: Gravity.

Explanation:

Earth and other objects would have fly off into space in a straight line if there would have been no gravity in between objects.

The gravity can be defined as the force between two objects in space which keeps two objects together in the space.

It is also responsible for holding the objects in space, making them move on their orbits, not allowing the heavenly bodies to crash.

So, there would be no gravity the objects will fall off in a straight line and none of the objects would be at its specified position.

3 0

4 years ago