he components needed in order for an experiment to be valid is a hypothesis, a control, and variables.
Answer:
20.11 g.
Explanation:
What is given?
c (specific heat of iron) = 0.450 J/g °C.
Q (heat energy) = 179.85 J.
ΔT (change of temperature) = |31.42 °C - 51.29 °C| = 19.87 °C.
What do we need? Mass of iron (m)
Step-by-step solution:
Let's see the formula of specific heat:

Where c is specific heat, Q is heat energy, m is mass and ΔT is the change of temperature.
We just have to solve for 'm' to find the mass of iron and replace the given data that we have, like this:

The mass of the iron would be 20.11 g.
Answer:
Atomic mass of element X = 115 g/mol (Approx)
Explanation:
Given:
Amount of XCl3 = 10.69 gram
Amount of X = 5.55 gram
Find:
Atomic mass of element X
Computation:
Moles of Cl = [Mass of Cl / Molar mass of Cl )
Moles of Cl = [(10.69 - 5.55 ) / 35.5]
Moles of Cl = 0.14479 (Approx)
Moles of X = 0.14479 / 3
Moles of X = 0.04826
Atomic mass of element X = 5.55 / 0.04826
Atomic mass of element X = 115 g/mol (Approx)
Answer:
The correct answer would be C) Support