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Nataly [62]
3 years ago
8

The diagram shows a transformer. Based on the diagram the voltage at the second winding is ____ v

Physics
2 answers:
weqwewe [10]3 years ago
4 0

Answer:

60V

Explanation:

Karolina [17]3 years ago
3 0

Answer:

60V

Explanation:

240V/12 loops = 20 volts per loop.

20 * 3 = 60 volts  

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State and prove bessel inequality​
maria [59]

Statement :- We assume the orthagonal sequence {{\{\phi\}}_{1}^{\infty}} in Hilbert space, now {\forall \sf \:v\in \mathbb{V}}, the Fourier coefficients are given by:

{\quad \qquad \longrightarrow \sf a_{i}=(v,{\phi}_{i})}

Then Bessel's inequality give us:

{\boxed{\displaystyle \bf \sum_{1}^{\infty}\vert a_{i}\vert^{2}\leqslant \Vert v\Vert^{2}}}

Proof :- We assume the following equation is true

{\quad \qquad \longrightarrow \displaystyle \sf v_{n}=\sum_{i=1}^{n}a_{i}{\phi}_{i}}

So that, {\bf v_n} is projection of {\bf v} onto the surface by the first {\bf n} of the {\bf \phi_{i}} . For any event, {\sf (v-v_{n})\perp v_{n}}

Now, by Pythagoras theorem:

{:\implies \quad \sf \Vert v\Vert^{2}=\Vert v-v_{n}\Vert^{2}+\Vert v_{n}\Vert^{2}}

{:\implies \quad \displaystyle \sf ||v||^{2}=\Vert v-v_{n}\Vert^{2}+\sum_{i=1}^{n}\vert a_{i}\vert^{2}}

Now, we can deduce that from the above equation that;

{:\implies \quad \displaystyle \sf \sum_{i=1}^{n}\vert a_{i}  \vert^{2}\leqslant \Vert v\Vert^{2}}

For {\sf n\to \infty}, we have

{:\implies \quad \boxed{\displaystyle \bf \sum_{1}^{\infty}\vert a_{i}\vert^{2}\leqslant \Vert v\Vert^{2}}}

Hence, Proved

5 0
2 years ago
Read 2 more answers
A +26.3 uC charge qy is repelled by a force
Musya8 [376]

Answer:

+1.46×10¯⁶ C

Explanation:

From the question given above, the following data were obtained:

Charge 1 (q₁) = +26.3 μC = +26.3×10¯⁶ C

Force (F) = 0.615 N

Distance apart (r) = 0.750 m

Electrical constant (K) = 9×10⁹ Nm²/C²

Charge 2 (q₂) =?

The value of the second charge can be obtained as follow:

F = Kq₁q₂ / r²

0.615 = 9×10⁹ × 26.3×10¯⁶ × q₂ / 0.750²

0.615 = 236700 × q₂ / 0.5625

Cross multiply

236700 × q₂ = 0.615 × 0.5625

Divide both side by 236700

q₂ = (0.615 × 0.5625) / 236700

q₂ = +1.46×10¯⁶ C

NOTE: The force between them is repulsive as stated from the question. This means that both charge has the same sign. Since the first charge has a positive sign, the second charge also has a positive sign. Thus, the value of the second charge is +1.46×10¯⁶ C

5 0
2 years ago
Someone please hellpp!!! Will mark brainliest
____ [38]

<em>Answer:</em>

<em>r=x+y</em>

<em>sorry if its not correct you can delete if you want.</em>

6 0
3 years ago
A cat chases a mouse across a 1.2 m high table. The mouse steps out of the way, and the cat slides off the table and strikes the
Drupady [299]
The cat has two directions of motions:
The horizontal motion = Dx = 2.2 m
The vertical motion = Dy = -1.3 m (negative sign indicates that the cat is falling)
a = 9.8 m/sec^2
Vy = zero (since you are not moving up)

From the laws of motion:
<span>Dy = Vyt + 0.5ayt^2 
</span>-1.3 = 0(t) + 0.5(-9.8)t^2
<span>t = 0.52s
</span>
Then, again using the laws of motion (but for the horizontal direction this time)
Dx = Vxt 
<span>2.2 = Vx0.52 </span>
<span>Vx = 2.2/0.52 </span>
<span>= 4.23 m/s 
</span>
<span>Therefore the cat's speed when it slid off the table is 4.23 m/s horizontally.</span>



7 0
3 years ago
What are three properties of electromagnetic waves?
Zolol [24]

The three properties of electromagnetic waves are; they travel at the speed of light, they include ultraviolet waves, and they can transfer energy through empty space.

<h2>Further Explanation</h2><h3>A wave</h3>
  • A wave is a transmission of a disturbance. It involves transmission of energy from one point which is the source to another point.
  • Waves may be classified depending on the need for a transmission medium or based on the vibration of particles relative to the direction of wave motion.
  • Waves may be either transverse or longitudinal based on the direction of wave motion relative to the vibration of particles
  • Additionally waves may be classified as either electromagnetic wave or mechanical based on the need for a transmission medium.
<h3>Electromagnetic waves  </h3>
  • Electromagnetic waves are types of waves that do not require a material medium for transmission.
  • All waves of the electromagnetic spectrum are electromagnetic transverse waves that do not require a material medium for transmission.
  • They include; radio waves, microwaves, infrared, visible light, ultra-violet, x-rays, and gamma rays.
  • All waves of the electromagnetic spectrum travel with a speed of light, 3.0 x10^8 m/s.
  • Additionally, electromagnetic waves possess energy that is given by; E = hf; where h is the plank's constant and f is the frequency.

keywords: Wave, electromagnetic wave, electromagnetic spectrum

<h2>Learn more about: </h2>
  • Waves: brainly.com/question/5354733
  • Electromagnetic waves: brainly.com/question/5354733
  • Electromagnetic spectrum: brainly.com/question/5354733
  • Velocity, speed and wavelength: brainly.com/question/11898955

Level: High school

Subject: Physics

Topic: Electromagnetic spectrum

Sub-topic: Properties of an electromagnetic waves

5 0
3 years ago
Read 2 more answers
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