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3 years ago

Which point lies on the line with point slope equation : y+5=2(x+8)

Physics

2 answers:

erik [133]3 years ago

7 0

A. (-8, -5)
the answer is A

insens350 [35]3 years ago

6 0

Answer:

A. (-8,-5)

Explanation:

If you fill in A you get

-5 + 5 = 2(-8+ 8)

0 = 0

So this point is on the line

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Distinguish between thermal energy, temperature, and heat. (BE SPECIFIC & use physics vocabulary)

xz_007 [3.2K]

Thermal energy can be defined as specific thermodynamic quantities as a part of energy transfer such as heat, which is a form of thermal energy flowing from hotter to colder objects. Temperature is a physical property of an object which specify whether the subject is hot or cold.

Explanation:

Difference between thermal energy, temperature and heat

Thermal Energy

Thermal energy is the total kinetic energy of molecules bundled up in the object. This energy is the heat exerted by the object which forms its temperature.

Temperature

In technical terms, temperature is the average kinetic energies measurement of molecules and atoms, present in an object. Simply, we can say, temperature defines how hot or how cold is a substance. Temperature relies on the kinetic energy of particles.

Heat

Transfer of thermal energy from a hotter to colder objects. Heat is different from temperature. Temperature is the mark to define how hot a substance is whereas, heat is the flow of thermal energy.

3 0

3 years ago

(a) What is the cost of heating a hot tub containing 1440 kg of water from 10.0°C to 40.0°C, assuming 75.0% efficiency to take h

BaLLatris [955]

Answer:

a) $E = 6.024\,USD$ , For m kilograms, it is 4184m J., 3600000 joules, b) $i = 88.200\,A$

Explanation:

a) The amount of heat needed to warm water is given by the following expression:

$Q_{needed} = m_{w}\cdot c_{w}\cdot (T_{f}-T_{i})$

Where:

$m_{w}$ - Mass of water, measured in kilograms.

$c_{w}$ - Specific heat of water, measured in $\frac{J}{kg\cdot ^{\circ}C}$ .

$T_{f}$ , $T_{i}$ - Initial and final temperatures, measured in $^{\circ}C$ .

Then,

$Q_{needed} = (1440\,kg)\cdot \left(4184\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (40^{\circ}C - 10^{\circ}C)$

$Q_{needed} = 180748800\,J$

The energy needed in kilowatt-hours is:

$Q_{needed} = 180748800\,J\times \left(\frac{1}{3600000}\,\frac{kWh}{J} \right)$

$Q_{needed} = 50.208\,kWh$

The electric energy required to heat up the water is:

$E = \frac{50.208\,kWh}{0.75}$

$E = 66.944\,kWh$

Lastly, the cost of heating a hot tub is: (USD - US dollars)

$E = (66.944\,kWh)\cdot \left(0.09\,\frac{USD}{kWh} \right)$

$E = 6.024\,USD$

The heat needed to raise the temperature a degree of a kilogram of water is 4184 J. For m kilograms, it is 4184m J. Besides, a kilowatt-hour is equal to 3600000 joules.

b) The current required for the electric heater is:

$i = \frac{Q_{needed}}{\eta \cdot \Delta V \cdot \Delta t}$